GRE Questions

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P = Rs. 6250, R = 14 %  & T = (146/365) years = 2/5 years .

 S.I=Rs.6250*14*25100=Rs.350

Let the cost price of a ball is Rs.x
Given, on selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls
The equation is :
17x - 720 = 5x
Solving the equation
we get x = 60
Therefore, cost price of a ball is Rs. 60.

Let the article costs 'X' to A
Cost price of B = 1.2X
Cost price of C = 0.75(1.2X) = 0.9X
Cost price of D = 1.4(0.9X) = 1.26X = 252
Amount paid by A for the article = Rs. 200.

5 C in an OF denotes 5 Circles in an Olympic Flag.

These are riddles of type

12 S of the Z

52 W in a Y.

350 days = (350/7=50 weeks) i.e  No odd days,

 So it will be a Saturday.

Let the original rate be R%. Then, new rate = (2R)%.

Note: Here, original rate is for 1 year(s); the new rate is for only 4 months i.e.1/3 year(s).

 725*R*1100+362.50*2R*1100*3=33.50

=> (2175 + 725) R = 33.50 x 100 x 3

=>  (2175 + 725) R = 10050

=>  (2900)R = 10050

 => R=100502900=3.46

Original rate = 3.46%

How many times can you subtract 10 from 100, for this if we go through logically, it is only 1 time. For the first time if we subtract 10 from 100, then there will no 100 to subtract from.

Hence, it is only 1 time we can subtract 10 from 100.