GRE Questions

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Let the sum be Rs. 100. Then,

S.I. for first 6 months = Rs.[ (100 x 10 x 1)/(100 x 2) ]= Rs.5

S.I. for last 6 months =Rs.[(102 x 10 x 1)/(100 x 2) ] = Rs.5.25

So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs. 110.25

Effective rate = (110.25 - 100) = 10.25%

Given (2a + 3b)/(5a - 3b) = 23/5
=> 10a + 15b = 115a - 69b
=> 105a = 84b => 5a = 4b
a/b = 4/5 => a=4 & b=5
=> bxa = 5x4 = 20.

C.I = P1+r100t-1

594.5 = 58001+r1002-1

 594.55800+1=1+r1002

r100=1.05-1=0.05=> r = 5 % .

Let rate = R% and time = R years.

Then, 1200×R×R100=432

 12R2=432

=> R = 6.

In physics, we know that the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Hence, An object that has kinetic energy must be in motion i.e, moving.

Draw out the diagram and you will see that the width of the picture becomes 8.5 - 3 = 5.5

The length becomes 10 - 3 = 7. The area is now 5.5 x 7 = 38.5

Let the sum be Rs. x.

I  gives, S.I. = Rs. 7000 and T = 7 years.

II gives, Sum + S.I. for 5 years = 2 x Sum Sum = S.I. for 5 years.

Now, S.I. for 7 years = Rs. 7000.

therefore, S.I. for 1 year =  Rs. 1000.

Thus, I and II both are needed to get the answer.

The computer that process both analog and digital is called Hybrid computer.