GRE Questions

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19 C in a CB means 19 Coins in a Carrom Board.

We have 9 white coins, 9 black coins and one red coin in a carrom board.

Here total parts of milk and water in the solution is 6+2 = 8 parts.

1part = 640/8 = 80

old mixture contains 6parts of milk and 2 parts of water(6:2).

To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same.

i.e, 4 x 80 = 320 ml.

Here in 100P2, P says that permutations and is defined as in how many ways 2 objects can be selected from 100 and can be arranged.

That can be done as,

100 P2 = 100!/(100 - 2)!

= 100 x 99 x 98!/98!

= 100 x 99 

= 9900.

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

A) As prime minister is an honorable person it must start with an Article 'The'. 

D) a fake jobs => a indicates it is singular, so job will come.

Screws weight = 90x100 = 9000gms
bolts weight = 100 x 150 = 15000gms
weight = screws + bolts => 24000 gms =>24 kg
Given entire box weight = 35.5kg
empty box = entire box weight - weight => 35.5kg - 24kg => 11.5kg
so the empty box is 11.5kg.

The given series follows the rule,
+(11x1), +(11x3), +(11x5), +(11x7), +(11x9),....

So starting from 7, 7 + 11 = 18, 18 + 33 = 51, 51 + 55 = 106, ...
So wrong number is 40 which is to be 51.

Obsrving the given arrangement, we find the following pattern:
If we arrange the words in the given input in the alphabetical order and then label them as 1,2,3,4,5,6, then the last step contains the words in the order 6,1,5,2,4,3. However, the position of only one word is alteredat each step.
Input:car on star quick demand fat
Step1: star car on quick demand fat
Step2: star car quick on demand fat
Step3: star car quick demand on fat

Hence, the answer is C