GRE Questions

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Let first no. be "k" and multiple be "l"...start value of y with 3
then,
[(k x y) + {l x (l-1)}]
Thus, we get

15 x 3 + 3 x 2 = 51
51 x 4 + 4 x 3 = 216
216 x 5 + 5 x 4 = 1100
1100 x 6 + 6 x 5 = 6630
6630 x 7 + 7 x 6 = 46452

Therefore, the missing number is 6630.

Let the two conditioners be A and B

'A' cools at 40min

'B' at 45min

Together = (a x b)/(a + b)

= (45 x 40)/(45 + 40)

= 45 x 40/85

= 21.1764

= 22 min (approx).

The given number series follows a pattern that,

9

9 x 0.5 + 0.5 = 5

5 x 1 + 1 = 6

6 x 2 + 2 = 14

14 x 4 + 4 = 60 (not equals to 56)

60 x 8 + 8 = 488.

Hence, the odd one in the given number series is 56.

The given number series is 1, 3, 10, 41, 206, ?

It follows a pattern that,

1

1 x 2 + 1 = 3

3 x 3 + 1 = 10

10 x 4 + 1 = 41

41 x 5 + 1 = 206

206 x 6 + 1 = 1237

Hence, the next number in the given number series is 1237.

The letter of the word are written in a reverse order and then each letter is moved one step backward to obtain the code.