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Q:

The average age of 80 boys in a class is 15 years. The average age of a group of 15 boys in the class is 16 years and the average age of another 25 boys in the class is 14 years. What is the average age of the remaining boys in the class?

A) 15.25 years B) 14 years
C) 14.75 years D) Cannot be determined
 
Answer & Explanation Answer: A) 15.25 years

Explanation:

Total sum of age of 80 students of the class = 15 X 80 = 1200 years
15 students → 15 X 16 = 240 years
25 students → 25 X 14 = 350 years
Sum of 40 students = 590 years
Total age of remaining 40 students = 1200 – 590 = 610
So, average age = 15.25 years

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Filed Under: Average
Exam Prep: Bank Exams

0 1842
Q:

Two partners invest Rs 12500 and Rs 8500 respectively in a business and agree that 60% of the profit should be divided equally between them and the remaining profit is to be treated as interest on capital. If one partner gets Rs 240 more than the other, find the total profit made in the business.

A) 3250 B) 4050
C) 3550 D) 3150
 
Answer & Explanation Answer: D) 3150

Explanation:

Clearly, If 60 % is equally divided then remaining 40% of total profit will be divided between 2 persons A and B in ratio of (profit of A) : (profit of B)= 12,500 : 8500 = 125 : 85 = 25:17
now difference in amount = 25-17 = 8 this difference = 240
therefore 40% of total profit = 240*(25+17)/(25-17) = 1260
∴ 100% profit = 1260 / 40 × 100 = 3150

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Filed Under: Partnership
Exam Prep: Bank Exams

2 6116
Q:

If the ratio of area of rectangle to its perimeter is 60:11. And length and breadth are in the ratio 6 : 5. Find length of rectangle.

A) 40 units B) 30 units
C) 13 units D) 24 units
 
Answer & Explanation Answer: D) 24 units

Explanation:

Ratio of length and breadth is 6 : 5
∴ Length = 6x
Breadth = 5x
∴ Area = l x b = 30x2
∴ Perimeter = 2 (l + b) = 2(6x + 5x) =22x
∴ (30*x*x)/(22x)= 60/11
∴ X = 4
∴ Length = 6x = 6 x 4 = 24 units

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Filed Under: Area
Exam Prep: Bank Exams

2 5112
Q:

Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

Quantity I: if the length of a rectangle is increased by 20% while the breadth of the rectangle is decreased by 10% then find percentage change in area of the rectangle?

Quantity II: if the side of a triangle is increased by 30% while the height of a triangle is decreased by 20% then find the percentage change in area of the triangle?

A) Quantity I > Quantity II B) Quantity I ≥ Quantity II
C) Quantity I< Quantity II D) Quantity I < Quantity II
 
Answer & Explanation Answer: A) Quantity I > Quantity II

Explanation:

Quantity I= 20% - 10% - (20*10/100) % = +8%

Quantity II= 30% - 20% - (30*20/100)% = +4%

Hence Quantity I > Quantity II

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Filed Under: Percentage

0 1974
Q:

Given equations are solved on the basis of a certain system. Find the correct answer for the unsolved equation on that basis :

2 + 4 + 6 = 48 and

3 + 2 + 8 = 48 ,

then 2 + 5 + 7 = ?

A) 48 B) 70
C) 14 D) 59
 
Answer & Explanation Answer: B) 70

Explanation:
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Filed Under: Verbal Reasoning - Mental Ability

0 1185
Q:

Each question contains Quantity I and Quantity II. Read the contents carefully and answer your questions accordingly.

Quantity I: there are three numbers in the ratio 5:6:10. The sum of the largest and the smallest numbers is 126 more than the other number. Find the largest number?

Quantity II: 12% of first number is equal to 25 % second number. The difference of these two numbers is 78. Then find the largest number?

A) Quantity I > Quantity I B) Quantity I ≥ Quantity II
C) Quantity I < Quantity II D) Quantity I < Quantity II
 
Answer & Explanation Answer: C) Quantity I < Quantity II

Explanation:

Quantity I= Let the three numbers will be 5x, 6x and 10x respectively

ATQ

10x+5x−6x=126 

9x=126 X=14

So largest number =10x=10×14=140

Quantity II=let x and y are two numbers

ATQ 

12% of x=25%of y And their difference is 78 

So first no.=150 2nd no.=72

Hence Quantity I < Quantity II

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Filed Under: Ratios and Proportions

0 2354
Q:

Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

Quantity I: 3 years ago the ratio of age of A and B is 3: 4 after 2 years the sum of their ages is 45. Then find the present age of A? 

Quantity II: 5 years ago, the ratio of age of p and Q id 3: 4 P’s age after 6 years is equal to the present age of Q. the find the present age of P?

 

 

A) Quantity I > Quantity II B) Quantity I ≥ Quantity II
C) Quantity I < Quantity II D) Quantity I < Quantity II
 
Answer & Explanation Answer: C) Quantity I < Quantity II

Explanation:

Quantity I= Let 3 year ago the age of A and B be 3x and 4x respectively

Then ATQ 3x+5+4x+5=45 X=5

Hence present age of A=3x+3=18year

Quantity II== Let 5 year ago the age of p and q be 3x and 4x respectively 

Then ATQ 

3x+11=4x+5 

X=6 Hence present age of P=3x+5=23

Hence Quantity I < Quantity II

 

 

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Filed Under: Problems on Ages

0 1604
Q:

If a denotes x , b denotes ÷ , c denotes + and d denotes ­ , then 8 a 3 c 24 b 12 d 19 = ?

A) 17 B) 7
C) 14 D) 8
 
Answer & Explanation Answer: B) 7

Explanation:
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Filed Under: Verbal Reasoning - Mental Ability

0 1064