Questions

Here crossing is AaBbCc x AaBbCc

As it is trihybrid cross,

we know, Number of zygotes formed = 4n, where n = 3

43 = 64

Given ratio of offsprings = 1 : 6 : m : 20 : m : 6 : 1

Now,  1 + 6 + m + 20 + m + 6 + 1 = 64

34 + 2m = 64

2m = 30

=> m = 15.

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