Questions

Virat Kohli becomes 1st player to win all 3 top ICC Awards :-

1. Sir Garfield Sobers Trophy for ICC Cricketer of the Year,

2. ICC Men’s Test Player of the Year &

3. ICC ODI Player of the Year for 2018.

India's rank in the latest ICC One Day International Rankings is Second. England tops the list followed by India, South Africa, New Zealand, Pakistan, Australia in the list.

Whereas India's rank in the latest ICC Test International Rankings is First followed by South Africa and England in 2nd and 3rd places.

XPath is an expressions to select a xml node in an XML document.

It allows the navigation on the XML document to the straight to the element where we need to reach and access the attributes.

TABC stands for Texas Alcoholic Beverage Commission. The Texas Alcoholic Beverage Commission regulates the sales, taxation, production, trade, and advertising of alcoholic beverages in Texas. Alcohol Seller/server Training regulated by this regulatory body is also called TABC Certification. It makes the rules the rest of us have to follow, and if you want to get a job serving alcohol in Texas, getting TABC certified is your first step.

Karst topography is a landscape formed from the dissolution of soluble rocks such as limestone, dolomite, and gypsum.

#include
#define MAX 50

void mergeSort(int arr[],int low,int mid,int high);
void partition(int arr[],int low,int high);

int main(){
  
    int merge[MAX],i,n;

    printf("Enter the total number of elements: ");
    scanf("%d",&n);

    printf("Enter the elements which to be sort: ");
    for(i=0;i<n;i++){
         scanf("%d",&merge[i]);
    }

    partition(merge,0,n-1);

    printf("After merge sorting elements are: ");
    for(i=0;i<n;i++){
         printf("%d ",merge[i]);
    }

   return 0;
}

void partition(int arr[],int low,int high){

    int mid;

    if(low<high){
         mid=(low+high)/2;
         partition(arr,low,mid);
         partition(arr,mid+1,high);
         mergeSort(arr,low,mid,high);
    }
}

void mergeSort(int arr[],int low,int mid,int high){

    int i,m,k,l,temp[MAX];

    l=low;
    i=low;
    m=mid+1;

    while((l<=mid)&&(m<=high)){

         if(arr[l]<=arr[m]){
             temp[i]=arr[l];
             l++;
         }
         else{
             temp[i]=arr[m];
             m++;
         }
         i++;
    }

    if(l>mid){
         for(k=m;k<=high;k++){
             temp[i]=arr[k];
             i++;
         }
    }
    else{
         for(k=l;k<=mid;k++){
             temp[i]=arr[k];
             i++;
         }
    }
  
    for(k=low;k<=high;k++){
         arr[k]=temp[k];
    }
}


Sample output:

Enter the total number of elements: 5
Enter the elements which to be sort: 2 5 0 9 1
After merge sorting elements are: 0 1 2 5 9