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Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 40 B) 20
C) 30 D) none of these
 
Answer & Explanation Answer: D) none of these

Explanation:

Let breadth = x metres.
Then, length = (x + 20) metres.

Perimeter =5300/23.50

2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.

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2 9781
Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 20% B) 30%
C) 40% D) 50%
 
Answer & Explanation Answer: D) 50%

Explanation:

Let original length = x and original breadth = y.

Original area = xy. 

New length = x/2 and New breadth=3y 

New area = 32xy 

Therefore,  Increase in area = New area-original area = 32xy-xy=12xy 

 

Therefore,  Increase % = increase in area original area*100=12xyxy*100=50 %

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47 45538
Q:

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A) 2520 B) 2420
C) 2320 D) 2620
 
Answer & Explanation Answer: A) 2520

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) = 2520 sq.m

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29 25912
Q:

What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?

A) 814 B) 714
C) 614 D) 713
 
Answer & Explanation Answer: A) 814

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm. 

Area of each tile = 41×41cm2  

Required number of tiles  = 1517×90241×41= 814

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26 24806
Q:

The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

A) 18 B) 28
C) 38 D) 48
 
Answer & Explanation Answer: A) 18

Explanation:

l2+b2=41 (or)   l2+b2=41  

Also, lb=20

l+b2=l2+b2+2lb  = 41 + 40 = 81

(l + b) = 9. 

Perimeter = 2(l + b) = 18 cm.

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Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

125 30039
Q:

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A) 30 B) 40
C) 50 D) 60
 
Answer & Explanation Answer: A) 30

Explanation:

Let the side of the square(ABCD) be x meters.

 

Then, AB + BC = 2x metres.

 

AC = 2x = (1.41x) m.

 

Saving on 2x metres = (0.59x) m.

 

Saving % =0.59x2x*100 = 30% (approx)

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Q:

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth.  The percentage of decrease in area is:

A) 18% B) 28%
C) 38% D) 48%
 
Answer & Explanation Answer: B) 28%

Explanation:

Let original length = x and original breadth = y.  

Decrease in area = xy - 80100x×90100y = (7/25)xy

 

Decrease % =    (7/25)xy * (1/xy) * 100 = 28%

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3 17851
Q:

The diagonal of the floor of a rectangular closet is 712 feet. The shorter side of the closet is 412 feet. What is the area of the closet in square feet?

A) 9 B) 18
C) 27 D) 36
 
Answer & Explanation Answer: C) 27

Explanation:

Other side = d2-s22254-814 = 1444 = 6 ft

 

  Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

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