Job Roles

Sigmoid colon or pelvic colon is a curved, S-shaped portion of the large intestine which is closest to the rectum and anus.

* It helps to transports fecal matter from the descending colon to the rectum and anus.

* It is the final segment of the colon.

When two dice are thrown simultaneously, the probability is n(S) = 6x6 = 36

Required, the sum of the two numbers that turn up is less than 12

That can be done as n(E)

= { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5) }

= 35

Hence, required probability = n(E)/n(S) = 35/36.

The difference between 4632 and 20000 is given by subtracting smaler number from the bigger number.

Here the bigger number is 20000

Smaller number is 4632

Now, subtracting 4632 from 20000

20000 - 4632 = 15368 and the resut is an even number.

Hence, The difference between 4632 and 20000 is 15368 and is an even number.

The given series follows a pattern that,

$$\begin{gathered} 4 + 32 = 4 + 9 = 13 \\ 13 + 52 = 13 + 25 = 38 \\ 38 + 72 = 38 + 49 = 87 \\ 87 + 92 = 87 + 81 = 198 \end{gathered}$$ 

Hence, the odd man in the given number series is 12.

The given number series is  21 56 102 160 231 316

21      56       102        160      231       316         416

   +35    +46       +58       +71      +85       +100

        +11      +12       +13      +14      +15

Hence, the next number in the given number series is 316 + 100 = 416.

Isotopes are variations of an element that have the same charge as the original element, but a different mass, which is caused by either more/less neutrons in the nucleus.

Percentage of students passed in English = 60%

Percentage of students passed in Hindi = 45%

Percentage of students passed in both subjects = 25%

ATQ,

Percentage of students passed in only English = 60 - 25 = 35%

Percentage of students passed in only Hindi = 45 - 25 = 20%

Therefore, Percentage of students failed = 100 - (35 + 25 + 20)

= 100 - 80 = 20%.

Given the ages of Sunitha and Pranitha are 40 years and 60 years.

Let before 'm' years, their ages be in the ratio of 3 : 5

ATQ,

40-m60-m = 35

=> 200 - 5m = 180 - 3m

=>2m = 20

=> m = 10 years.