Job Roles

Dr. Neelu Rohmetra from Jammu University has been appointed as one of the heads of IIMs. She became the first woman director of Indian Institute of Management Sirmaur, Himachal Pradesh. Dr. Neelu Rohmetra is the founder of the director of International Centre for Cross-Cultural Research and Human Resource Management (ICccR and HRM).

Indian Cricket team off-spin specialist Ravichandran Ashwin has become the fastest cricketer to take 250 wickets in the Test matches. Ashwin surpassed Australian fast bowler Dennis Keith Lillee to reach the milestone of 250 Test wicket. Thus Ravichandran Ashwin has become the sixth Indian bowler to reach 250 test wickets.

By trial and error method, we get
2880/3 = 960 is not a perfect square
2880/4 = 720 is not a perfect square
2880/5 = 576 which is perfect square of 24
Hence, 5 is the least number by which 2880 must be divided in order to make it into a perfect square.

He has gain = 15 - 12 = 3,
Gain% = (3/12) x 100 = (100/4) = 25.
He has 25% gain.

From statement (b)
Average of 11 players = 11 x 28 = 308
Average of 10 players = 10 x 27.3 = 273
Age of captain = 308 - 273 = 35.

From the Statement (a) we can say that captain's age (C) = y + 11 ...(1) where y-youngers age
From the statement (c),the averge age of 3groups of 3players each was given,
It means total 9 players age was given indirectly,
1st group: 25 x 3 = 75
2nd group: 28 x 3 = 84
3rd group: 30 x 3 = 90
Total  is 75 + 84 + 90 = 249
Now {C + Y + (9 players age sum)}/11 = 28
Y + 11 + Y + (249) = 28 x 11=308
2Y+260=308
2Y = 308-260 = 40 ==> Y=24 ==> C(captain's age)= Y+11 = 24+11 = 35

Therefore, statement b alone or a & c only is the answer.

Let X = Time taken for each of Type B Problems(100 Problems)
And 2X = Time taken for each of Type A problems(50 problems)

Total time period = 3hrs = 3 x 60min = 180 minutes

100X + 50(2X) = 180
100X + 100X = 180
200X = 180 min

X = 180/200
X = 0.90 min

By convertiing into seconds,

X = 0.90 x 60 seconds
X = 54 sec

So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds
= 5400/60sec = 90 minutes.

Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 65.
i.e (58+58+x)/3 = 65
116 + x = 195
x = 79 marks.

Therefore, the maximum marks he can score in maths is 79.

No. of people who read Hindu = 285
No. of people who read TOI = 127
No. of people who read IE = 212
Now,
No. of people who read Hindu and TOI both is = 20
No. of people who read TOI and IE both is = 35
No. of people who read Hindu and IE both is = 29
Let No. of people who read Hindu , TOI and IE all is = x ;
So, only Hindu is = 285-20-29-x = 236-x ;
Only TOI is = 127-20-35-x = 72-x ;
Only IE is = 212-35-29-x = 148-x ;
Now, 236-x + 72-x + 148-x + 20 + 29 + 35 + x + 50 = 500 590 -2x = 500
So, x = 45 this is the value who read all the 3 dailies.
So, No. of people who read only one paper is = 236-45 + 72-45 + 148-45 = 191 + 27 + 103 = 321.