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Q:

Count the number of cubes in the given figure.

A) 80 B) 87
C) 89 D) 90
 
Answer & Explanation Answer: C) 89

Explanation:

In the figure, there are 9 columns containing 5 cubes each, 7 columns containing 4 cubes each, 5 columns containing 3 cubes each and 1 column containing 1 cube.

 

 

 

Total number of cubes = (9 x 5) + (7 x 4) + (5 x 3) + (1 x 1) = 89

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24 8824
Q:

Count the number of cubes in the given figure.

A) 64 B) 66
C) 68 D) 70
 
Answer & Explanation Answer: C) 68

Explanation:

In the figure, there are 34 columns containing 2 cubes each.

  Total number cubes = (34 x 2) = 68

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28 4214
Q:

Determine the number of rectangles and hexagons in the following figure.

A) 30, 5 B) 32, 3
C) 28, 5 D) 30, 3
 
Answer & Explanation Answer: A) 30, 5

Explanation:

The figure may be labelled as shown

 

 

Rectangles :

 

The simplest rectangles are CVSR, VETS, RSWM and STKW i.e 4 in number.

 

The rectangles composed of two components each are CETR, VEKW, RTKM and CVWM i.e 4 in number.

 

The rectangles composed of three components each are ACRP, PRMO, EGHT and THIK i.e 4 in number.

 

The rectangles composed of four components each are CEKM, AVSP, PSWO,VGHS and SHIW i.e 5 in number.

 

The rectangles composed of five components each are AETP, PTKO, CGHR and RHIM i.e 4 in number.

 

The rectangles composed of six components each are ACMO and EGIK i.e 2 in number.

 

The rectangles composed of eight components each are AGHP, PHIO, AVWO and VGIW i.e 4 in number.

 

The rectangles composed of ten components each are AEKO and CGIM i.e 2 in number.

 

AGIO is the only rectangle having sixteen components

 

Total number of rectangles in the given figure = 4 + 4 + 4 + 5 + 4 + 2 + 4 + 2 + 1 = 30.

 

Hexagons :

 

The hexagons in the given figure are CDEKLM, CEUKMQ, CFHJMQ, BEUKNP and BFHJNP. So, there are 5 hexagons in the given figure.

 

 

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48 9731
Q:

Count the number of triangles and squares in the given figure.

A) 36 triangles, 7 Squares B) 38 triangles, 9 Squares
C) 40 triangles, 7 Squares D) 42 triangles, 9 Squares
 
Answer & Explanation Answer: C) 40 triangles, 7 Squares

Explanation:

The figure may be labelled as shown 

 

 

Triangles :

 


The Simplest triangles are BGM, GHM, HAM, ABM, GIN, IJN, JHN, HGN, IKO, KLO, LJO, JIO, KDP, DEP, ELP, LKP, BCD and AFE i.e 18 in number

 

The triangles composed of two components each are ABG, BGH, GHA, HAB, HGI, GIJ, IJH, JHG, JIK, IKL, KLJ,LJI, LKD, KDE, DEL and ELK i.e 16 in number.

 

The triangles composed of four components each are BHI, GJK, ILD, AGJ, HIL and JKE i.e 6 in number.

 

Total number of triangles in the figure = 18 + 16 + 6 =40.

 

Squares :

 


The Squares composed of two components each are MGNH, NIOJ, and OKPL i.e 3 in number

 

The Squares composed of four components each are BGHA, GIJH, IKJL and KDEL i.e 4 in number

 

Total number of squares in the figure = 3 + 4 =7

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78 13771
Q:

Using numbers from 0 to 9 the number of 5 digit telephone numbers that can be formed is

A) 1,00,000 B) 59,049
C) 3439 D) 6561
 
Answer & Explanation Answer: C) 3439

Explanation:

The numbers 0,1,2,3,4,5,6,7,8,9 are 10 in number while preparing telephone numbers any number can be used any number of times.

 

This can be done in 105ways, but '0' is there

 

So, the numbers starting with '0' are to be excluded is 94 numbers.

 

 Total 5 digit telephone numbers = 105- 94 = 3439

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5 3344
Q:

In how many ways the letters of the word 'DESIGN' can be arranged so that no consonant appears at either of the two ends?

A) 240 B) 72
C) 48 D) 36
 
Answer & Explanation Answer: C) 48

Explanation:

DESIGN = 6 letters

 

No consonants appear at either of the two ends. 

2 x 4P4 =  2 x 4 x 3 x 2 x 1=  48

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10 9234
Q:

In How many ways can the letters of the word 'CAPITAL' be arranged in such a way that all the vowels always come together?

A) 360 B) 720
C) 120 D) 840
 
Answer & Explanation Answer: A) 360

Explanation:

CAPITAL = 7

 

Vowels = 3 (A, I, A)

 

Consonants = (C, P, T, L)

 

5 letters which can be arranged in  5P5=5!

 

Vowels A,I = 3!2!

 

No.of arrangements = 5! x 3!2!=360

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4 5186
Q:

The number of ways that 8 beads of different colours be strung as a necklace is 

A) 2520 B) 2880
C) 4320 D) 5040
 
Answer & Explanation Answer: A) 2520

Explanation:

The number of ways of arranging n beads in a necklace is (n-1)!2=(8-1)!2=7!2 = 2520 

(since n = 8)

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27 15802