Job Roles Questions and Answers

Q:

If $A = \frac{l o g_{3} (2187)}{5}$ and $B = l o g_{243} (2187)$ , then which one of the following is correct?

A) A	B) A=B
C) A>B	D) can't be determined

Answer & Explanation Answer: B) A=B

Explanation:

Given $A = \frac{\log_{3} (2187)}{5} a n d B = \log_{243} (2187)$

$B = \log_{3^{5}} (2187) = \frac{\log_{3} (2187)}{5}$

=> A

Therefore, A = B

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Filed Under: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

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Q:

If a, b, c be the $p^{t h}, q^{t h} a n d r^{t h}$ terms of a GP then the value of (q-r) log a + (r-p) log b + (p-q) log c is :

A) 0	B) 1
C) -1	D) pqr

Answer & Explanation Answer: A) 0

Explanation:

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Q:

Find the logarithm of 144 to the base $2 \sqrt{3}$ :

A) 2	B) 4
C) 8	D) None of these

Answer & Explanation Answer: B) 4

Explanation:

$\log_{2 \sqrt{3}} (144) = 4$

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Filed Under: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

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Q:

A car mechanic purchased four old cars for Rs. 1 lakh. He spent total 2 lakh in the maintenance and repairing of these four cars. what is the average sale price of the rest three cars to get 50% total profit if he has already sold one of the four cars at Rs. 1.2 lakh?

A) 1.5 lakh	B) 1.1 lakh
C) 1.2 lakh	D) 1.65 lakh

Answer & Explanation Answer: B) 1.1 lakh

Explanation:

Total cost of 4 cars = 1+2 = 3 lakh

Total S.P of 4 cars = 3 x 1.5 = 4.5 lakh ( $S i n c e S . P = \frac{(100 + G a i n %)}{100} x C . P$ )

S.P of 1 car = 1.2 lakh

S.P of rest 3 cars = 4.5 - 1.2 = 3.3 lakh

Average S.P of all the 3 cars = 1.1 lakh

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

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Q:

A, B and C invest in the ratio of 3 : 4: 5. The percentage of return on their investments are in the ratio of 6 : 5 : 4. Find the total earnings, If B earns Rs. 250 more than A :

A) Rs. 6000	B) Rs. 7250
C) Rs. 5000	D) None of these

Answer & Explanation Answer: B) Rs. 7250

Explanation:

A B C

investment 3x 4x 5x

Rate of return 6y% 5y% 4y%

Return $\frac{18 x y}{100} \frac{20 x y}{100} \frac{20 x y}{100}$

Total = (18+20+20) = $\frac{58 x y}{100}$

B's earnings - A's earnings = $\frac{2 x y}{100}$ = 250

Total earning = $\frac{58 x y}{100}$ = 7250

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

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Q:

Rahul went to purchase a Nokia mobile handset, the shopkeeper told him to pay 20% tax if he asked the bill. Rahul manages to get the discount of 5% on the actual saleprice of the mobile and he paid the shopkeeper Rs. 3325 without tax. Besides he manages to avoid to pay 20% tax on the already discounted price, what is the amount of discount that he has gotten?

A) 750	B) 375
C) 875	D) 525

Answer & Explanation Answer: C) 875

Explanation:

CP = 100, SP (with tax) =120

New SP = 100 - 5 = 95

Effective discount = 120 - 95 = 25

So, at SP of 95 ----> discount = 25

and at SP of 3325 -----> discount = $\frac{25}{95} \times 3325 = 875$

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Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

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Q:

Due to reduction of 25% in price of oranges a customer can purchase 4 oranges more for Rs. 16. what is original price of an orange?

A) Rs 1	B) Rs 1.33
C) Rs 1.5	D) Rs 1.6

Answer & Explanation Answer: B) Rs 1.33

Explanation:

Recall it is based on inverse proportion or product constancy concept.

Reducion in price increase in amount

25% 1/4 1/3 33.33% = 4 oranges

It means original number of oranges = 4 x 3 = 12

original price of oranges = 16/12 = Rs. 1.33

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

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Q:

A trader sold an article at a loss of 5% but when he increased the selling price by Rs.65 he gained 3.33% on the cost price. If he sells the same article at Rs. 936, what is the profit percentage?

A) 15%	B) 16.66%
C) 20%	D) data insufficient

Answer & Explanation Answer: C) 20%

Explanation:

103.33 CP- 0.95 CP = 65

CP = Rs. 780

profit (%) = (936 - 780)/780 x 100 = 20%

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Filed Under: Profit and Loss
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