Job Roles Questions and Answers

Q:

ITC sells one product at a profit of 20% another at a loss of 20% at the same selling price. What is the loss incurred by ITC?

A) 1%	B) 2%
C) 4%	D) 0%

Answer & Explanation Answer: C) 4%

Explanation:

loss % = ${(\frac{c o m m o n g a i n o r l o s s}{10})}^{2}$ %

= (20/10)x(20/10)% = 4%

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

18 9663

Q:

A person sold two cows each for Rs.9900. If he gained 10% on one and lost 20% on the other, then which of the following is true?

A) He Gained Rs. 200	B) He lost Rs. 200
C) He neither gained nor lost	D) None of the above

Answer & Explanation Answer: D) None of the above

Explanation:

The CP of profitable cow = 9900/1.1 = 9000

and profit = Rs. 900

The CP of loss yielding cow = 9900/0.8 = 12375

and loss = Rs. 2475

so, the net loss = 2475 - 900 = 1575

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

26 17187

Q:

The ratio of cost price and marked price of an article is 2:3 and ratio of percentage profit and percentage discount is 3:2 . what is the discount percentage?

A) 16.66%	B) 20%
C) 25%	D) 33.33%

Answer & Explanation Answer: A) 16.66%

Explanation:

CP : MP = 2x : 3x

=> Profit = x

( %) profit : (%) discount = 3:2

Let CP = 2000, SP = 300

But $\frac{3 x}{100} \times 200 + \frac{2 x}{100} \times 300 = 100$

=> x = 8.33%

Discount 2x = 16.66%

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Filed Under: Indian Politics
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

50 23108

Q:

A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage?

A) 116%	B) 166.66%
C) 60%	D) 100%

Answer & Explanation Answer: B) 166.66%

Explanation:

Let the cost price of 1-liter pure milk be Re.1, then

$\{\begin{cases} 6 l i t e r s (m i l k) \to C . P = R s . 6 \\ 2 l i t e r s (w a t e r) \to C . P = R s . 0 \end{cases} \to C P = R s . 6 o n l y$

8 litre mixture =>

SP => 8 x 2 = Rs. 16

Profit % = $\frac{16 - 6}{6} x 100 = \frac{1000}{6} = 166.66 %$

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

384 56628

Q:

A Shepherd had n goats in the year 2000. In 2001 the no.of goats increased by 40% . In 2002 the no. of goats declined to 70%. In 2003 the no. of goats grew by 30%. In 2004, he sold 10% goats, then he had only 34,398 goats. The percentage increase of the no.of goats in this duration was:

A) 14.66%	B) 16.66%
C) 20%	D) 33.33%

Answer & Explanation Answer: A) 14.66%

Explanation:

There is no need to use the no of goats i.e (34,398). let initially thete be 1000 goats then

1000 -----> 1400 -----> 980 -----> 1274 ----->1146.6

Thus the % increase = (1146.6-1000)/100 x 100= 14.66%

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

7 8549

Q:

In a factory there are three types of Machines M1 , M2 and M3 which produces 25%, 35% and 40% of the total products respectively. M1, M2 and M3 produces 2% , 4% and 5% defective products, respectively. What is the percentage of non-defective products?

A) 89%	B) 97.1%
C) 96.1%	D) 86.1%

Answer & Explanation Answer: C) 96.1%

Explanation:

Non- defective products

$\frac{25 x 0.98 + 35 x 0.96 + 40 x 0.95}{100} x 100 = 96.1$

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

22 13182

Q:

A man lost half of its initial amount in the gambling after playing 3 rounds. The rule of gambling is that if he wins he will receive Rs. 100, but he has to give 50% of the total amount after each round.Luckily he won all the three rounds. The initial amount with which he had started the gambling was :

A) 500/3	B) 700/3
C) 300	D) 600

Answer & Explanation Answer: B) 700/3

Explanation:

Let the initial amount be x (with gambler), then

$[[(x + 100) \frac{1}{2} + 100] \frac{1}{2} + 100] \frac{1}{2} = \frac{x}{2}$

=> x = 700/3

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

19 14344

Q:

Each edge of a cube is increased by 20% then the percentage increase in surface area of the cube is :

A) 144%	B) 40%
C) 44%	D) 72.8%

Answer & Explanation Answer: C) 44%

Explanation:

The surface area of a cube = 6 $a^{2}$ = 6 $s i d e^{2}$

New Surface area = 6 x 1.44 $a^{2}$

Therefore, $\frac{0.44 a^{2}}{a^{2}} x 100 = 44$ %

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

13 8278

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