Analyst Interview Questions and Answers

Q:

A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be

A) Rs. 387	B) Rs. 441
C) Rs. 469	D) Rs. 503

Answer & Explanation Answer: B) Rs. 441

Explanation:

Given principal amount = Rs. 8000

Time = 3yrs

Rate = 5%

C.I for 3 yrs = $8000 x \frac{105}{100} x \frac{105}{100} x \frac{105}{100} - 8000 = Rs . 1261$

Now, C.I for 2 yrs = $8000 x \frac{105}{100} x \frac{105}{100} = Rs . 820$

Hence, the required difference in C.I is 1261 - 820 = Rs. 441

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Filed Under: Compound Interest
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Q:

A merchant commences with a certain capital and gains annually at the rate of 30 per cent. At the end of 2 years he has worth Rs 10,000. What was the original capital?

A) Rs. 4987	B) Rs. 5148
C) Rs. 5917	D) Rs. 6254

Answer & Explanation Answer: C) Rs. 5917

Explanation:

Let the Original capital amount be Rs. P

Given after 2 years the amount is Rs. 10000

Rate of interest = 30%

According to the question,

$P x \frac{130}{100} x \frac{130}{100} = 10000 = > P = \frac{1000000}{169} = 5917$

Therefore, the capital amount P = Rs. 5917

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Filed Under: Percentage
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Q:

Solve this logical Math puzzle?

logical_thinking_puzzle1536132282.jpg image

Answer

Let that something be 'x'

From the given data,

x + x/5 = 21

5x + x/5 = 21

6x = 21 x 5

=> x = 17.5

Hence, that something is x = 17.5.

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Subject: Math Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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Q:

A tennis ball machine serves a ball vertically into the air from a height of 2 feet, with an initial speed of 110 feet per second. After how many seconds does the ball attain its maximum height?

A) 2.87 sec	B) 3.44 sec
C) 4.65 sec	D) 5.41 sec

Answer & Explanation Answer: B) 3.44 sec

Explanation:

It is launched vertically with an initial speed of 110 ft/sec.

It will reach maximum height when the speed drops to 0.

Vo=110 feet per second

ho=2 feet

So, h(t) = -16t^2 +110t +2

Take the derivative: h'(t) = 110 -32t

The maximum height will be at the inflection when the derivative crosses the x-axis, then h'(t)=0.

So, set h'(t)=0 and solve for t:

0 = 110 -32t

-110 = -32t

t=3.4375

t=3.44 seconds.

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Filed Under: Physics
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3 6739

Q:

GUI stands for

A) Graphical Universal Interface	B) Graph Use Interface
C) Graphical Unique Interface	D) Graphical User Interface

Answer & Explanation Answer: D) Graphical User Interface

Explanation:

GUI stands for Graphical User Interface.

A Graphical User Interface is a computer interface that allows users to interact with a device through graphical elements such as pictures and animations, as opposed to text-based commands.

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Filed Under: Computer
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9 6735

Q:

The memory unit is one part of

A) Input Device	B) Central Processing Unit
C) Control Unit	D) Output device

Answer & Explanation Answer: B) Central Processing Unit

Explanation:

In a computer, memory is one part of Central processing unit i.e, CPU.

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Q:

Which observation proves that a cell is a eukaryote?

A) It contains DNA	B) It contains ribosomes
C) It has a cell membrane	D) It has DNA inside a nucleus

Answer & Explanation Answer: D) It has DNA inside a nucleus

Explanation:

Eukaryotic cells all have a nucleus. Eukaryotes are organisms that are multicellular, although there are some examples of single cellular eukaryotes. So eukaryotic cells can be either cell with a nucleus or a eukaryotic organism's cell.

The most important feature to judge whether it has nucleus membrane.

And for other choices, they are the common features of eukaryote and prokaryote.

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Filed Under: Biology
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9 6730

Q:

The Value of $[\log (\tan (1^{0})) + \log (\tan (2^{0})) + \dots \dots + \log (\tan (89^{0}))]$ is

A) -1	B) 0
C) 1/2	D) 1

Answer & Explanation Answer: B) 0

Explanation:

$= [\log \tan (1^{0}) + \log \tan (89^{0})] + [\log \tan (2^{0}) + \log \tan (88^{0})] + \dots \dots + [\log \tan (45^{0})]$

$= \log [\tan (1^{0}) \times \tan (89^{0})] + \log [\tan (2^{0}) \times \tan (88^{0})] + \dots \dots + \log (1)$

$[∵ \tan (90 - θ) = c o t θ a n d \tan (45^{0}) = 1]$

= log 1 + log 1 +.....+log 1

= 0.

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Filed Under: Logarithms
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