Q:
A polygon has 44 diagonals, then the number of its sides are ?
Answer & Explanation
Answer: C) 11
Explanation: Let the number of sides be n.
The number of diagonals is given by nC2 - n
Therefore, nC2 - n = 44, n>0
nC2 - n = 44
n2 - 3n - 88 = 0
n2 -11n + 8n - 88 = 0
n(n - 11) + 8(n - 11) = 0
n = -8 or n = 11.
As n>0, n will not be -8. Therefore, n=11.
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