Bank Clerk Questions

The arrangement in the alphabetical order is Shout, Skirt, Slaughter, Specify, Straight.

The word in the middle is Slaughter.

FCH₂COOH is the strongest acid out of all.

Since the electron withdrawing inductive effect (-I effect) of the halogens decreases in the order of F>Cl> Br> I , therefore the acidic strength of the α- halo acids decreases in the same order.

FCH₂COOH  >  ClCH₂COOH   >   BrCH₂COOH   >   ICH₂COOH.

The colour of coal is Black. In the code language ,black is called orange. So, the colour of coal is Orange.

Famous for Hot water springs and homeland for Hoolock Gibbons and Golden Langurs, The Garampani Wildlife Sanctuary is situated in Karbi Anglong of Diphu area. One of the oldest Sanctuary containing Hot water spring and waterfalls and surrounded by Nambour Sanctuary having 51 rare species of Orchid. It has a total area of 6 sq. Km.

Suppose there are 9 balls

Let us give name to each ball B1 B2 B3 B4 B5 B6 B7 B8 B9

Now we will divide all the balls into 3 groups.

Group1 - B1 B2 B3

Group2 - B4 B5 B6

Group3 - B7 B8 B9

Step1 - Now weigh any two groups. Let's assume we choose Group1 on left side of the scale and Group2 on the right side.

So now when we weigh these two groups we can get 3 outcomes.

Weighing scale tilts on left - Group1 has a heavy ball.
Weighing scale tilts on right - Group2 has a heavy ball.
Weighing scale remains balanced - Group3 has a heavy ball.
Lets assume we got the outcome as 3. i.e Group 3 has a heavy ball.

Step2 - Now weigh any two balls from Group3. Lets assume we keep B7 on left side of the scale and B8 on right side.

So now when we weigh these two balls we can get 3 outcomes.

Weighing scale tilts on left - B7 is the heavy ball.
Weighing scale tilts on right - B8 is the heavy ball.
Weighing scale remains balanced - B9 is the heavy ball.
The conclusion we get from this Problem is that each time weigh. We element 2/3 of the balls.

As we came to conclusion that Group3 has the heavy ball from Step1, we remove 6 balls from the equation i.e (2/3) of 9.

Simillarly we do the ame thing for the Step2.

Now going with this conclusion. We have 6561 balls.

Step - 1

Divided into 3 groups

Group1 - 2187Balls

Group2 - 2187Balls

Group3 - 2187Balls

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

Step - 2

Divided into 3 groups

Group1 - 729Balls

Group2 - 729Balls

Group3 - 729Balls

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

Step - 3

Divided into 3 groups

Group1 - 243Balls

Group2 - 243Balls

Group3 - 243Balls

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

Step - 4

Divided into 3 groups

Group1 - 81Balls

Group2 - 81Balls

Group3 - 81Balls

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

Step - 5

Divided into 3 groups

Group1 - 27Balls

Group2 - 27Balls

Group3 - 27Balls

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

Step - 6

Divided into 3 groups

Group1 - 9Balls

Group2 - 9Balls

Group3 - 9Balls

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

Step - 7

Divided into 3 groups

Group1 - 3Balls

Group2 - 3Balls

Group3 - 3Balls

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

Step - 8

So now when we weigh 2 balls out of 3 we can get 3 outcomes.

Weighing scale tilts on left - left side placed is the heavy ball.
Weighing scale tilts on right - right side placed is the heavy ball.
Weighing scale remains balanced - remaining ball is the heavy ball.
So the general answer to this question is, it is always multiple of 3 steps.

For 9 balls  32= 9. therefore 2 steps

For 6561 balls 38 = 6561 therefore 8 steps

72 --- 9
? ---- 1

=> Down Stream = 8

45 ---- 9 
? ---- 1

=> Up Stream = 5

Speed od current S = ?

S = (8 - 5)/2 = 1.5 kmph.

If an outstanding check of the previous month clears the bank (is paid by the bank) in the current month, you simply remove that check from the list of outstanding checks.

If an outstanding check of the previous month does not clear the bank in the current month, the check will remain on the list of outstanding checks until the month that it does clear the bank.

In the bank reconciliation process, the total amount of the outstanding checks is deducted from the balance appearing on the bank statement.

 The UP government changed the name of Gorakhpur and Agra Airports as well as the name of the department of welfare of the differently abled.

 The Gorakhpur Airforce Station has been renamed as Mahayogi Goraknath Airport after the founder of the Nath monastic movement.

The Agra Airport will be renamed after Pandit Deen Dayal Upadhyay airport. The Department of Disabled Welfare will now be known as 'Divyang Jan Vikas Empowerment'.