Bank Clerk Questions and Answers with Explanation, Job Roles

Q:

Which of the following is not a correct variable type?

A) real	B) char
C) float	D) double

Answer & Explanation Answer: A) real

Explanation:

A variable provides us with named storage that our programs can manipulate. Each variable in C++ has a specific type, which determines the size and layout of the variable's memory the range of values that can be stored within that memory and the set of operations that can be applied to the variable.

The name of a variable can be composed of letters, digits, and the underscore character. It must begin with either a letter or an underscore. Upper and lowercase letters are distinct because C++ is case-sensitive −

Basic types of variables:

1. bool

Stores either value true or false.

2. char

Typically a single octet (one byte). This is an integer type.

3. int

The most natural size of an integer for the machine.

4. float

A single-precision floating point value.

5. double

A double-precision floating point value.

6. void

Represents the absence of type.

7. wchar_t

A wide character type.

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Filed Under: C++
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10 6315

Q:

Ajay and his wife Reshmi appear in an interview for two vaccancies in the same post. The Probability of Ajay's selection is 1/7 and that of his wife Reshmi's selection is 1/5. What is the probability that only one of them will be selected?

A) 5/7	B) 1/5
C) 2/7	D) 2/35

Answer & Explanation Answer: C) 2/7

Explanation:

P( only one of them will be selected) = p[(E and not F) or (F and not E)]

= $P [(E \cap F) \cup (F \cap E)]$

= $P (E) P (F) + P (F) P (E)$

= $\frac{1}{7} \times \frac{4}{5} + \frac{1}{5} \times \frac{6}{7} = \frac{2}{7}$

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Filed Under: Probability
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17 6312

Q:

What position did Babe Ruth play

A) Only 1st base	B) Both pitcher and out fielder
C) Only out fielder	D) Only pitcher

Answer & Explanation Answer: B) Both pitcher and out fielder

Explanation:

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Filed Under: General Awareness
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1 6310

Q:

Where is the DNA located in a eukaryotic cell?

A) Nucleus	B) Chromosomes
C) Mitochondria	D) All of the above

Answer & Explanation Answer: D) All of the above

Explanation:

In eukaryotic cells, DNA is located in the nucleus, chromosomes and the mitochondria. Most of the DNA is present in the nucleus and some amount in the chromosomes and mitochondria.

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Filed Under: General Science
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4 6309

Q:

If $\log_{3} (30)$ = $\frac{1}{a}$ and $\log_{5} (30) = \frac{1}{b}$ then the value of $3 \log_{30} (2)$ is:

A) 3(1+a+b)	B) 2(1-a-b)
C) 3(1-a-b)	D) 3(1+a-b)

Answer & Explanation Answer: C) 3(1-a-b)

Explanation:

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Filed Under: Logarithms
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25 6299

Q:

What has 3 feet but cannot walk?

Answer

We know that 1 yard = 3 feet.

A yardstick which is used for measurement has 3 feet long but it cannot walk.

Workspace

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Subject: Logic Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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7 6294

Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

A) Rs.6000	B) Rs.4500
C) Rs.7500	D) Rs.5000

Answer & Explanation Answer: D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

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Filed Under: Percentage
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9 6290

Q:

Which ionization process requires the most energy?

A) C3+ (g) → C4+ (g) + e-	B) C (g) → C+ (g) + e-
C) C2+ (g) → C3+ (g) + e-	D) C+ (g) → C2+ (g) + e-

Answer & Explanation Answer: A) C3+ (g) → C4+ (g) + e-

Explanation:

We know that each successive IE is greater than the previous one, because each ionization process removes one electron and hence increases the total attractive force on the remaining electrons from the nucleus. Hence, C3+ (g) → C4+ (g) + e- needs more energy.

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Filed Under: Chemistry
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1 6289

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