Bank Clerk Questions


Q:

A cuboid of dimension 24cm x 9cm x 8 cm is melted and smaller cubers are of side 3 cm is formed.find how many such cubes can be formed ?

A) 64 B) 56
C) 48 D) 40
 
Answer & Explanation Answer: A) 64

Explanation:

Volume of cuboid = (24 x 9 x 8) cm = 1728 cu.cm
Volume of small cube = (3 x 3 x 3) cm = 27 cu.cm


So, No. of small cubes formed = 1728/27 = 64.

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Filed Under: Volume and Surface Area
Exam Prep: CAT , Bank Exams , AIEEE
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5 10030
Q:

What holds the sides of the DNA ladder together?

A) Polar covalent bonds B) Ionic bonds
C) Metallic bonds D) Covalent bonds
 
Answer & Explanation Answer: D) Covalent bonds

Explanation:

Deoxyribose, which is a pentose, and a phosphate group are the two molecules together form the two sides of the DNA i.e, A sugar (deoxyribose) and a phosphate.

DNA is a double-stranded molecule twisted into a helix (think of a spiral staircase). Each spiraling strand, comprised of a sugar-phosphate backbone and attached bases, is connected to a complementary strand by non-covalent hydrogen bonding between paired bases. The bases are adenine (A), thymine (T), cytosine (C) and guanine (G). A and T are connected by two hydrogen bonds. G and C are connected by three hydrogen bonds.

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Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , GATE
Job Role: Analyst , Bank Clerk , Bank PO

16 10028
Q:

If a+b+c =21 what is the total number of positive integral solutions?

A) 109 B) 190
C) 901 D) 910
 
Answer & Explanation Answer: B) 190

Explanation:

Number of positive integral solutions =  n-1Cr-1 = C220 = 190

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
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6 10028
Q:

The probability that z lies between 0 and 3.01

A) 0.4987 B) 0.5
C) 0.9987 D) 0.1217
 
Answer & Explanation Answer: A) 0.4987

Explanation:

Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have

P(z<0) = 0.5

P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987.

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT
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37 10027
Q:

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ?

A) 10 yrs B) 11 yrs
C) 12 yrs D) 13 yrs
 
Answer & Explanation Answer: A) 10 yrs

Explanation:

Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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4 10022
Q:

The accounting software Tally was developed by

A) Wipro B) TCS
C) HCL D) Infosys
 
Answer & Explanation Answer: B) TCS

Explanation:

Tally is one of the best business accounting software for accounting, inventory, payroll. It is economical and one of the most popular ERP software solutions available in the industry.

Tally, an accounting software was developed by the multinational company TCS - Tata Consultancy Services.

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Filed Under: Bank Interview
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12 10003
Q:

Sony is one-fifth the age of her mother 15 years ago and Sony’s brother is three-fifth the age of his mother 10 years ago. If the sum of Sony and her brother’s ages is 31 then how old is Sony's mother ? 

A) 40 B) 50
C) 60 D) 70
 
Answer & Explanation Answer: B) 50

Explanation:

Sony and her brother's age sum is 31
Let Sony's mother's age be 'x'.
Now the conditions given for both of their ages related to their mom is
1/5(x-15) + 3/5(x-10) = 31
x-15 + 3x-30 = 155
4x-45 = 155
4x = 200
x = 50
So, Mother's age = 50.

Cross verification : 15 years ago age = 35 => Sony age = 7
10 years ago age = 40 => bro age = 24

Sum = 24 + 7 = 31.

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Filed Under: Problems on Ages
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9 9999
Q:

Round robin scheduling falls under the category of

A) Preemptive scheduling B) Non preemptive scheduling
C) Both A & B D) None of the above
 
Answer & Explanation Answer: A) Preemptive scheduling

Explanation:

Round-robin (RR) is one of the algorithms employed by process and network schedulers in computing. It falls under the category of Preemptive scheduling. In computing, the running task is interrupted for some time without requiring its cooperation and resumed later when the priority task has finished its execution. This is called preemptive scheduling. 

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Filed Under: Computer
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6 9998