Bank Clerk Questions and Answers with Explanation, Job Roles

Q:

Jaduguda mines are famous for

A) mica deposits	B) uranium deposits
C) gold deposits	D) iron ore

Answer & Explanation Answer: B) uranium deposits

Explanation:

The Jaduguda Mine also known as Jadugoda or Jadugora is a Uranium mine in Jaduguda village in the Purbi Singhbhum district of the Indian state of Jharkhand.

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Filed Under: Indian Geography
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

13 6834

Q:

When 5% is lost in grinding Maize, a country has to import 20 million bags; but when only 2% is lost, it has to import only 15 million bags. Find the quantity of Maize, which grows in the country ?

A) 188 million	B) 166 2/3 million
C) 192 3/4 million	D) None

Answer & Explanation Answer: B) 166 2/3 million

Explanation:

5% - 2% = 3%
=> 3% ------ 5 million bags
100% ---- ?
=> 166 2/3 million bags.

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Filed Under: Arithmetical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

8 6834

Q:

In what time a 360 m. long train moving at the speed of 44 km/hr will cross a 140 m. long bridge ?

A) 36 sec	B) 39 sec
C) 41 sec	D) 43 sec

Answer & Explanation Answer: C) 41 sec

Explanation:

Speed = 44 kmph x 5/18 = 110/9 m/s

We know that, Time = distance/speed

Time = (360 + 140) / (110/9)

= 500 x 9/110 = 41 sec.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

12 6833

Q:

The Ghodazari Wildlife Sanctuary (GWS) will come up in which state?

A) Maharashtra	B) Karnataka
C) Tamil Nadu	D) Odisha

Answer & Explanation Answer: A) Maharashtra

Explanation:

The Maharashtra Government has recently approved Ghodazari Wildlife Sanctuary in Chandrapur district as a new wildlife sanctuary in the state.

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Filed Under: Indian Geography
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk

16 6829

Q:

A man sold two flats for Rs. 4.15 lakhs each. On one he gained 2% and on the other he lost 2%. What percent is the effect of the sale on the whole ?

A) 0.25 %	B) 0.04 %
C) 0.5 %	D) 0 %

Answer & Explanation Answer: B) 0.04 %

Explanation:

In this type cases we always have loss only.

Loss% = ${(\frac{C o m m o n G a i n o r L o s s}{10})}^{2}$ = ${(\frac{2}{10})}^{2}$ = 1/25 = 0.04 %

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Filed Under: Profit and Loss
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

11 6829

Q:

Which observation proves that a cell is a eukaryote?

A) It contains DNA	B) It contains ribosomes
C) It has a cell membrane	D) It has DNA inside a nucleus

Answer & Explanation Answer: D) It has DNA inside a nucleus

Explanation:

Eukaryotic cells all have a nucleus. Eukaryotes are organisms that are multicellular, although there are some examples of single cellular eukaryotes. So eukaryotic cells can be either cell with a nucleus or a eukaryotic organism's cell.

The most important feature to judge whether it has nucleus membrane.

And for other choices, they are the common features of eukaryote and prokaryote.

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Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk

9 6827

Q:

Mr. X sold two properties P1 and P2 for Rs 1,00,000 each. He sold property P1 for 20% less than what he paid for it. What is the percentage of profit of property P2, so that he is not in gain or loss on the sale of two properties?

A) 33.33%	B) 29.97%
C) 25%	D) 22.22%

Answer & Explanation Answer: A) 33.33%

Explanation:

Let 'A' be the cost price of property P1.

Then from the given data, the selling price of P1 = Rs. 1,00,000

He got 20% loss on selling P1

$\Rightarrow A - \frac{20 A}{100} = 100000 \Rightarrow A = 1, 25, 000$

Therefore, the amount he lossed on selling P1 = 25,000

As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000

But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000

Hence, the profit percentage on P2 = $\frac{Gain}{CP} x 100 = \frac{25000}{75000} x 100 = \frac{100}{3} = 33.33 %$

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

10 6827

Q:

The Value of $[\log (\tan (1^{0})) + \log (\tan (2^{0})) + \dots \dots + \log (\tan (89^{0}))]$ is

A) -1	B) 0
C) 1/2	D) 1

Answer & Explanation Answer: B) 0

Explanation:

$= [\log \tan (1^{0}) + \log \tan (89^{0})] + [\log \tan (2^{0}) + \log \tan (88^{0})] + \dots \dots + [\log \tan (45^{0})]$

$= \log [\tan (1^{0}) \times \tan (89^{0})] + \log [\tan (2^{0}) \times \tan (88^{0})] + \dots \dots + \log (1)$

$[∵ \tan (90 - θ) = c o t θ a n d \tan (45^{0}) = 1]$

= log 1 + log 1 +.....+log 1

= 0.

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Filed Under: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

27 6822

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