Q:
      
      
         
            
Find by how much percentage the average of first 10 odd numbers (starting from 1) is greater than the last term ?
         
       
      
      
      
          
      
      
          Answer & Explanation
         Answer: B) 900/19 %         
         
Explanation: First ten odd numbers form an arithmetic progression of the form
1,3,5,7,9......
here a = first term = 1
d = common difference = 2
Average of first n numbers = (2a + (n - 1)d)/2
n th term of the AP = a + (n - 1)d
Substituting a = 1, d = 2 and n = 10 in the above formulas 
average of first 10 numbers = 10
10 th term of the AP = 19
Therefore average of first 10 terms is 19 - 10 = 9 greater than
the last term. Hence the average is greater than the sum by
9/19 X 100 = 900/19 %
       
      
      
      
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