Bank Clerk Questions

Kelvin temperature scale is the temperature scale that is based upon absolute zero.

Benign prostatic hyperplasia (BPH) also called benign prostatic hypertrophy (or) prostate gland enlargement is a noncancerous enlargement of the prostate gland that can lead to lower urinary tract symptoms (LUTS).

It is the diagnosis characterized by proliferation of the cellular elements of the prostate.

Symptoms ::

As the prostate gets larger, it starts to pinch the urethra. This causes symptoms that affect your urine flow, such as:

* Dribbling when you finish

* A hard time getting started

* A weak stream, or you pee in stops and starts.

A Union territory is a type of administrative division in India. Unlike the other states which have their own state governments, union territories are ruled by the central government. There are 7 union territories in India. They are ::

• National Capital Territory of Delhi – Delhi.

• Chandigarh – Chandigarh.

• Daman and Diu – Daman.

• Dadra and Nagar Haveli – Silvassa.

• Pondicherry – Puducherry.

• Andaman and Nicobar Islands – Port Blair.

• Lakshadweep – Kavaratti.

DNA is not a single stranded and does not have amino acids. Hence options, b & C are eiminated. Dna is a double helix structure containing nucleobase—either cytosine (C), guanine (G), adenine (A), or thymine (T)—as well as a monosaccharide sugar called deoxyribose and a phosphate group. 

The axial skeleton is the part of the skeleton that consists of the bones of the head and trunk of a vertebrate. In the human skeleton, it consists of 80 bones and is composed of six parts; the skull bones, the ossicles of the middle ear, the hyoid bone, the rib cage, sternum and the vertebral column.

Bones of shoulder, thigh and foot are the part of appendicular skeleton. 

Hence, Vertebral column is the part of axial skeleton.

Let length of platform be ‘y’metres.

Then, at the platform,Distance travelled = y + (length of train) = (y + 480)m

Then, Speed of train = (y + 480)m / (3x60) sec = (y+480)/180 ...(1)

Also, at the pole,Distance travelled = length of train = 480m

Then, Speed of train = 480m / 30sec = 16 m/s ...(2)

Equating eq.(1) & eq.(2), we get,

(y+480)/180 = 16(y+480) = 16 x 180 = 2880

y = 2880 –480 = 2400m or 2.4 km long platform.