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Q:

Out of 120 students in aschool, 5% can play all the three games Cricket, Chess and Carroms. If so happens that the number of players who can play any and only two games is 30. The number of students who can play the Cricket alone is 40. What is the total number of those who can play Chess alone or Carroms alone ?

A) 45 B) 44
C) 46 D) 24
 
Answer & Explanation Answer: B) 44

Explanation:

k11483174138.jpg image

 

Given U=120

5% of 120 = 6

Therefore, Students who can play Chess alone or Carroms alone =  120 - (30+40+6)= 44

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Filed Under: Logical Venn Diagram
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97 18370
Q:

Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ?

A) 11.8 B) 12.9
C) 13.7 D) 14.5
 
Answer & Explanation Answer: D) 14.5

Explanation:

Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.
k/l = 5/x ------ (1)
k = m - 18 ------ (2)
m + 9 = 47 ------ (3)
k - l = m ----- (4)
(3) => m = 47 - 9 = 38 years
(2) => k = 38 -18 = 20 years
(1) => 20/l = 5/x => l = 4x
(4) => 4x - 20 = 38
=> 4x = 58 => x = 14.5

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Filed Under: Problems on Ages
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27 18369
Q:

If every seconds Saturday and all Sundays are holidays in a 30 days month beginning on Saturday, then how many working days are there in that month ? (Month starts from Saturday)

A) 25 B) 22
C) 24 D) 23
 
Answer & Explanation Answer: D) 23

Explanation:

As month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days will be Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all.

Hence, no. of working days = 30 – 7 =23

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Filed Under: Calendar
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55 18365
Q:

A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture ?

A) 5 lit B) 10 lit
C) 15 lit D) 20 lit
 
Answer & Explanation Answer: B) 10 lit

Explanation:

Number of liters of water in 150 liters of the mixture = 20% of 150 = 20/100 x 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 x (150 + P)
120 + 4P = 150 + P => P = 10 liters.

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Filed Under: Alligation or Mixture
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9 18316
Q:

If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x+y is equal to  ?

A) 5 B) 4
C) 3 D) 2
 
Answer & Explanation Answer: D) 2

Explanation:

Since 653xy is divisible by 5 as well as 2, so y = 0.
Now, 653x0 must be divisible by 8.
So, 3x0 must be divisible by 8. This happens when x = 2
x + y = (2 + 0) = 2.

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Filed Under: Numbers
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26 18304
Q:

What do eukaryotic cells have that prokaryotic cells do not?

A) Nucleus B) Cytoplasm
C) Ribosomes D) DNA
 
Answer & Explanation Answer: A) Nucleus

Explanation:

ep1527656002.jpg image

Eukaryotic cells contain membrane-bound organelles, including a nucleus. Eukaryotes can be single-celled or multi-celled, such as you, me, plants, fungi, and insects.

 

Whereas Prokaryotic cells do not contain a nucleus or any other membrane-bound organelle. Bacteria are an example of prokaryotes.

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Filed Under: Biology
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34 18286
Q:

Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ?

A) Rs.2010 B) Rs.2200
C) Rs.2000 D) Rs.2100
 
Answer & Explanation Answer: C) Rs.2000

Explanation:

Let money invested by Raghu = Rs. x
Money invested by Trishul = 9/10 x = 0.9x
Money invested by Vishal = 9/10x * 110/100 = 0.99x
Also, x+0.9x+0.99x = 5780
= x= 5780/2.89 = 2000

Therefore, amount invested by Raghu is Rs. 2000.

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Filed Under: Partnership
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12 18270
Q:

Milk and water are mixed in a vessel A as 4:1 and in vessel B as 3:2. For vessel C, if one takes equal quantities from A and B, find the ratio of milk to water in C.

A) 1:9 B) 9:1
C) 3:7 D) 7:3
 
Answer & Explanation Answer: D) 7:3

Explanation:

Ratio of Milk and water in a vessel A is 4 : 1

 

Ratio of Milk and water in a vessel B is 3 : 2

 

Ratio of only milk in vessel A = 4 : 5

 

Ratio of only milk in vessel B = 3 : 5

 

Let 'x' be the quantity of milk in vessel C

 

Now as equal quantities are taken out from both vessels A & B

 

=> 4/5     :     3/5
               x 
  3/5-x          x - 4/5

 

=> 35-xx-45 = 11 (equal quantities)

 

=> x = 7/10

 

Therefore, quantity of milk in vessel C  = 7

 

=> Water quantity = 10 - 7 = 3

 

Hence the ratio of milk & water in vessel 3 is 7 : 3 

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Filed Under: Alligation or Mixture
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33 18261