Bank PO Questions


Q:

Count the number of triangles and squares in the given figure.

A) 36 triangles, 7 Squares B) 38 triangles, 9 Squares
C) 40 triangles, 7 Squares D) 42 triangles, 9 Squares
 
Answer & Explanation Answer: C) 40 triangles, 7 Squares

Explanation:

The figure may be labelled as shown 

 

 

Triangles :

 


The Simplest triangles are BGM, GHM, HAM, ABM, GIN, IJN, JHN, HGN, IKO, KLO, LJO, JIO, KDP, DEP, ELP, LKP, BCD and AFE i.e 18 in number

 

The triangles composed of two components each are ABG, BGH, GHA, HAB, HGI, GIJ, IJH, JHG, JIK, IKL, KLJ,LJI, LKD, KDE, DEL and ELK i.e 16 in number.

 

The triangles composed of four components each are BHI, GJK, ILD, AGJ, HIL and JKE i.e 6 in number.

 

Total number of triangles in the figure = 18 + 16 + 6 =40.

 

Squares :

 


The Squares composed of two components each are MGNH, NIOJ, and OKPL i.e 3 in number

 

The Squares composed of four components each are BGHA, GIJH, IKJL and KDEL i.e 4 in number

 

Total number of squares in the figure = 3 + 4 =7

Report Error

View Answer Report Error Discuss

Filed Under: Analytical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

78 13751
Q:

What do eukaryotic cells have that prokaryotic cells do not?

A) Nucleus B) Cytoplasm
C) Ribosomes D) DNA
 
Answer & Explanation Answer: A) Nucleus

Explanation:

ep1527656002.jpg image

Eukaryotic cells contain membrane-bound organelles, including a nucleus. Eukaryotes can be single-celled or multi-celled, such as you, me, plants, fungi, and insects.

 

Whereas Prokaryotic cells do not contain a nucleus or any other membrane-bound organelle. Bacteria are an example of prokaryotes.

Report Error

View Answer Report Error Discuss

Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

34 13747
Q:

A train covers a distance between station A and station B in 45 min.If the speed of the train is reduced by 5 km/hr,then the same distance is covered in 48 min.what is the distance between the stations A and B ?

A) 80 kms B) 60 kms
C) 45 kms D) 32 kms
 
Answer & Explanation Answer: B) 60 kms

Explanation:

Let 'd' be the distance and 's' be the speed and 't' be the time
d=sxt
45 mins = 3/4 hr and 48 mins = 4/5 hr
As distance is same in both cases;
s(3/4) = (s-5)(4/5)
3s/4 = (4s-20)/5
15s = 16s-80
s = 80 km.
=> d = 80 x 3/4 = 60 kms.

Report Error

View Answer Report Error Discuss

Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

18 13693
Q:

The perimeter of a square is equal to twice the perimeter of a rectangle of length 8cm and breadth 7cm. What is the circumference of a semicircle whose diameter is equal to the side of the square ?

A) 55.12 cm B) 22.54 cm
C) 42.51 cm D) 38.57 cm
 
Answer & Explanation Answer: D) 38.57 cm

Explanation:

We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cm
Given perimeter of square is twice the perimeter of rectangle = 2(30) = 60cm
Therefore, side of the square is = 1/4 x 60 = 15cm
Circumference of the required semicircle = πr + 2r = 227× 152 + 2×152 = 23.57 + 15 = 38.57cm.

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

6 13670
Q:

8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is :

A) 8/39 B) 15/39
C) 12/13 D) None of these
 
Answer & Explanation Answer: B) 15/39

Explanation:

P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize) 

 

 = 1-16C1× 14C1×12C1×10C116C4=1539

Report Error

View Answer Report Error Discuss

Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

64 13616
Q:

111 13 112 24 113 35 117 ?

A) 46 B) 57
C) 68 D) 79
 
Answer & Explanation Answer: D) 79

Explanation:

The given puzzle follows a pattern that,

Number - <last digit> <sum of all digits>.

111 - 13

112 - 24

113 - 35

So 

117 - 79

Report Error

View Answer Report Error Discuss

Filed Under: Number Puzzles
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

59 13597
Q:

In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ?

A) 6/7 B) 19/21
C) 7/31 D) 5/21
 
Answer & Explanation Answer: D) 5/21

Explanation:

Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁)

As remaining person can be any one among three couples left.

Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅
= (10 x 6)/252 = 5/21

Report Error

View Answer Report Error Discuss

Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

12 13595
Q:

What is the value of P in the following Equation ?

 192.5 × 19p = 197

A) 3.9 B) 4.1
C) 3.7 D) 4.5
 
Answer & Explanation Answer: D) 4.5

Explanation:

Given equation is  

  192.5 ×19p = 197   

Here it is in the form of am × an = am+n  

 Here m = 2.5 , n = p, m+n = 7

 => 2.5 + p = 7 

 => p = 7 - 2.5

 => p = 4.5

Report Error

View Answer Report Error Discuss

Filed Under: Mathematical Operations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

25 13594