Q:
Find the sum of the all the numbers formed by the digits 2,4,6 and 8 without repetition. Number may be of any of the form like 2,24,684,4862 ?
Answer & Explanation
Answer: B) 147320
Explanation: Sum of 4 digit numbers = (2+4+6+8) x x (1111) = 20 x 6 x 1111 = 133320
Sum of 3 digit numbers = (2+4+6+8) x x (111) = 20 x 6 x 111 = 13320
Sum of 2 digit numbers = (2+4+6+8) x x (11) = 20 x 3 x 11 = 660
Sum of 1 digit numbers = (2+4+6+8) x x (1) = 20 x 1 x 1 = 20
Adding All , Sum = 147320
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