Bank PO Questions

The central government has said that India has emerged as the 3rd largest aviation market in the world with a passenger traffic of over 10 crore reported for 2016-17. This was stated by minister of state for civil aviation Jayant Sinha at a media event on the achievements of the ministry of civil aviation on the completion of three years of the NDA government.

The researchers at IIT Kharagpur have developed a new technology to manufacture cheaper, quicker and pollution-free bio-fuel. The ‘soil-to-soil’ manufacturing technology developed at the P K Sinha Centre for bio-energy at IIT-KGP is in the process of being patented. The technique will ensure relatively quicker production of bio-fuel and the process is completely green. The green leafy part of corn and sugarcane plants, the waste part of paddy straw, bamboo, banana plant, pineapple and cotton plants, kans grass (kassh phool), castor plant and even non-edible weeds that grow in dry and waste land and a mix of all has been used by IIT-KGP to produce bio fuel. The project is funded by the Ministry of Petroleum and Natural Gas, Department of Science and Technology and the Ministry of Human Resource Development.

NUMERICAL has 9 positions in which 2, 4, 6, 8 are even positions.

And it contains 5 consonents i.e, N, M, R, C & L. Hence this cannot be done as 5 letters cannot be placed in 4 positions.

Therefore, Can't be determined.

Let the side of the square be 's' cm

length of rectangle = (s+5) cm

breadth of rectangle = (s-3)cm

(s+5) (s-3) = 

s2 - 5s - 3s - 15 = s2 

2s = 15

Perimeter of rectangle = 2(L+B) = 2(s+5 + s–3) = 2(2s + 2)

= 2(15 + 2) = 34 cm 

Given that train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 15 seconds.

Let the length of train K be Lk and that of train L be Ll

given that Lk = 3/4 Ll

As the train K and L crosses the pole in 30 seconds and 80 seconds respectively,
=> Speed of train K = sk = Lk/30

Speed of train L = sl = Ll/80

Lk = 3/4 Ll
=> sk = 3/4 Ll/(30) = Ll/40

Ratio of their speeds = sk : sl
= Ll/40 : Ll/80

=> 1/40 : 1/80  =  2 : 1

Given total number of students in the class = 21

So each student will have 20 greeting cards to be send or receive (21 - 1(himself))

Therefore, the total number of greeting cards exchanged by the students = 20 x 21 = 420.