Bank PO Questions and Answers with Explanation, Job Roles

Q:

Arrange the following words in an appropriate order

1. Rainbow 2. Rain 3. Sun 4. Happy 5. Child

A) 4, 2, 3, 5, 1	B) 4, 5, 1, 2, 3
C) 2, 1, 4, 5, 3	D) 2, 3, 1, 5, 4

Answer & Explanation Answer: D) 2, 3, 1, 5, 4

Explanation:

Firstly Rain falls and then Sun comes and Rainbow forms. After that Child sees the rainbow and feels Happy.

Report Error

View Answer Report Error Discuss

Filed Under: Logical Sequence of Words
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO

30 43490

Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

2. How many students are there in Class IX in the school?

A. 336 B.189 C. 335 D. 430

3. Which section has the maximum pass percentage in at least one of the two examinations?

A. A Section B. B Section C. C Section D. D Section

4. Which section has the maximum success rate in annual examination?

A. A Section B. B Section C. C Section D. D Section

5. Which section has the minimum failure rate in half yearly examination?

A. A section B. B section C. C section D. D section

Half yearly examinations were more difficult.

If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C

Explanation - Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

2. ANSWER : D

Explanation - Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

3. ANSWER : D

Explanation- Pass percentages in at least one of the two examinations for different sections are:

For Section A = $\frac{14 + 6 + 64}{28 + 14 + 6 + 64} \times 100 = \frac{84}{112} \times 100$ % = 75%

For Section B = $\frac{12 + 17 + 55}{23 + 12 + 17 + 55} \times 100$ % = 78.5%

For Section C = $\frac{8 + 9 + 46}{17 + 8 + 9 + 46} \times 100$ %= 78.75%

For Section D = $\frac{13 + 15 + 76}{27 + 13 + 15 + 76} \times 100$ %= 79.39%

Clearly ,the pass percentage is maximum for Section D

4. ANSWER : A

Explanation - Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

Success rate in annual exams in Section A= $\frac{14 + 64}{112} \times 100$ % = 69.64%

Similarly, success rate in annual exams in:

Section B = $\frac{12 + 55}{107} \times 100$ % = 62.62%

Section C = $\frac{8 + 46}{80} \times 100$ % = 67.5%

Section D = $\frac{89}{131} \times 100$ % = 67.94%

Clearly, the success rate in annual examination is maximum for Section A.

5. ANSWER : D

Explanation - Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

Failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Table Charts Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

138 43476

Q:

Which of the following is a popular programming language for developing multimedia webpages.

A) COBOL	B) Java
C) BASIC	D) Assembler

Answer & Explanation Answer: B) Java

Explanation:

Java is a general-purpose computer-programming language that is concurrent, class-based, object-oriented, and specifically designed to have as few implementation dependencies as possible.

Which_of_the_following_is_a_popular_programming_language_for_developing_multimedia_webpages1548652333.jpg image

Java is used to develop mobile apps, web apps, desktop apps, games and much more...

Report Error

View Answer Report Error Discuss

Filed Under: Computer
Exam Prep: Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer , Network Engineer , Project Manager , Software Architect

180 43362

Q:

If 1 1 1 1 = R
2 2 2 2 = T
3 3 3 3 = E
4 4 4 4 = N

Then 5 5 5 5 = ?

A) Y	B) Z
C) T	D) X

Answer & Explanation Answer: A) Y

Explanation:

If you add all the terms of the LHS of equality, then the last letter of the sum written in words would give you the RHS.

1 + 1 + 1 + 1 = 4 = FOUR

2 + 2 + 2 + 2 = 8 = EIGHT

3 + 3 + 3 + 3 = 12 = TWELVE

4 + 4 + 4 + 4 = 16 = SIXTEEN

So, following the same pattern.

5 + 5 + 5 + 5 = 20 = TWENTY

That gives us our answer to 5 5 5 5 = "Y".

Report Error

View Answer Report Error Discuss

Filed Under: Number Puzzles
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer , Network Engineer

86 43291

Q:

The length of a rectangle is twice its breadth if its length is decreased by 5cm and breadth is increased by 5cm, the area of the rectangle is increased by 75 sq cm. Find the length of the rectangle.

A) 30	B) 40
C) 50	D) 60

Answer & Explanation Answer: B) 40

Explanation:

let length = 2x and breadth = x then
(2x-5) (x+5) = (2x * x)+75
5x-25 = 75 => x=20
length of the rectangle = 40 cm

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

51 43160

Q:

The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 sq.m. The length of the hall is

A) 20	B) 25
C) 30	D) 35

Answer & Explanation Answer: C) 30

Explanation:

Let breadth = x m

Then, length = (x+5)m

Area of a rectangle = Length x Breadth

x(x+5) = 750

x² + 5x - 750= 0

(x+30)(x-25)= 0

x = 25 or x = -30

Hence, breadth x = 25m

=> Length = x + 5 = 25 + 5 = 30m.

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

72 43112

Q:

A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be

A) 7744	B) 8844
C) 5544	D) 4444

Answer & Explanation Answer: A) 7744

Explanation:

length of wire = $2 πr$ = 2 x (22/7 ) x 56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88 x 88 = 7744sq cm

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

77 42960

Q:

A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.

A) 136	B) 146
C) 166	D) 176

Answer & Explanation Answer: D) 176

Explanation:

area of the room = 544 x 374 sq.cm

size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm

area of 1 tile = 34x34 sq cm

no. of tiles required = (544 x 374) / (34 x 34) = 176

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

62 42918

Bank PO Questions

Quick Links