Q:
      
      
         
            
6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally?
         
       
      
      
      
          
      
      
          Answer & Explanation
         Answer: C) 36         
         
Explanation: Given 4men, 12 women and 20 children work for  2 days.
Workdone for 2 days by 4men, 12 women and 20 children = 
Therefore, remaining work = 1 -  = 
To complete the same work by only men in 1 day,
We know that M1 x D1 = M2 x D2
Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1
12 x 6 = M x 1
=> M = 12 x 6 = 72
=> But the remaining work = 1/2
Men required => 1/2 x 72 = 36
Only men required to Complete the remaining work in 1 day = 36.
 
       
      
      
      
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