Bank PO Questions


Q:

The more you take, the more you leave behind. What is that?

A) Pictures B) Hole
C) Clothes D) Footsteps
 
Answer & Explanation Answer: D) Footsteps

Explanation:

Yes, footsteps are what we take more, the more we leave behind. 

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Q:

Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of  gentlemen in the family?

A) 23 B) 92
C) 48 D) 52
 
Answer & Explanation Answer: A) 23

Explanation:

Total number of female members = 115

Let the number of males = x

Number of females = y

=> x + y = 115  ......(1)

According to the given data,

x + y(0.50) = 69 ......(2)

From (1) & (2), we get

0.5y = 46

=> y = 46 x 2 = 92

=> x = 115 - 92 = 23

 

Hence, required number of gentlemen in the family = x = 23.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

8 8739
Q:

In a certain code DOWN is written as '5@9#' and NAME is written as '#6%3'. How is MODE written in that code ?

A) 6@53 B) %@53
C) 53%# D) %#35
 
Answer & Explanation Answer: B) %@53

Explanation:

From the given information :

D O W N A M E == 5 @ 9 # 6 % 3
MODE = %@53

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Filed Under: Coding and Decoding
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

20 8738
Q:

1.12.91 is the first Tuesday. Which is the fourth Thursday of December 91  ?

A) 22.12.91 B) 25.12.91
C) 24.12.91 D) 23.12.91
 
Answer & Explanation Answer: B) 25.12.91

Explanation:

Given that 2.12.91 is the first Tuesday
Hence we can assume that 4.12.91 is the first Thursday

If we add 7 days to 4.12.91, we will get second Thursday
If we add 14 days to 4.12.91, we will get third Thursday
If we add 21 days to 4.12.91, we will get fourth Thursday

=> fourth Thursday = (4.12.91 + 21 days) = 25.12.91.

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Filed Under: Calendar
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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32 8734
Q:

What is the shortest phase of the cell cycle?

A) M B) G1
C) S D) G2
 
Answer & Explanation Answer: A) M

Explanation:

Longest and shortest phases Of cell cycle:

Shortest Phase - M phase or Mitotic phase.

Longest phase - G1 phase of the Interphase

Longest and shortest phases During Mitosis:

Longest Phase - Prophase

Shortest Phase - Anaphase

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Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

13 8729
Q:

A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ?

A) 74 B) 79
C) 72 D) 60
 
Answer & Explanation Answer: A) 74

Explanation:

Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12
To raise the average by one (from 14 to 15), he scored 12 more than the existing average.
Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.

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Filed Under: Average
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9 8727
Q:

Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ?

A) 50% B) 25%
C) 75% D) 60%
 
Answer & Explanation Answer: A) 50%

Explanation:

CP of 1000gm = Rs. 10
SP of 800gm = Rs. 12
SP of 1000gm =12x1000/800 = Rs. 15

Now take 1000gm as reference to calculate profit.
Profit=SP-CP=15-10=Rs. 5
Profit % = 5x100/10 = 50%

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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8 8724
Q:

A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ?

A) 1:3 B) 2:1
C) 3:2 D) 2:3
 
Answer & Explanation Answer: C) 3:2

Explanation:

Let us assume S as number of shirts and T as number of trousers
Given that each trouser cost = Rs.70 and that of shirt = Rs.30
Therefore, 70 T + 30 S = 810
=> 7T + 3S = 81......(1)
T = ( 81 - 3S )/7

We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of T
Simplifying by taking 3 as common factor i.e, 3(27-S) / 7
In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7

Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9

Hence for S, put T in eq(1), we get
S = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.
The ratio of T:S = 9:6 = 3:2.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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