Bank PO Questions


Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99 B) 100
C) 89 D) 1
 
Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

 

Distance travelled by P while it meets Q = d + 11

 

Distance travelled by Q while it meets P = d – 11

 

Distance travelled by Q while it meets R = d + 9

 

Distance travelled by R while it meets Q = d – 9

 

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

 

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

 

But given Ratio of speeds of P & R => P : R = 3 : 2

 SPSR = SPSQxSQSR = d+11d+9d-11d-9

 

=> d+11d+9d-11d-9 = 3/2

 

=>  d = 1, 99

 

=> d = 99 satisfies.

 

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
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16 7760
Q:

The correct order of events during meiosis is

A) prophase I, metaphase I, anaphase I, telophase I, cytokinesis, meiosis II. B) anaphase I, telophase I, prophase I, cytokinesis, meiosis II.
C) cytokinesis, metaphase I, anaphase I, telophase I, D) telophase I, prophase I, cytokinesis, meiosis II, anaphase
 
Answer & Explanation Answer: A) prophase I, metaphase I, anaphase I, telophase I, cytokinesis, meiosis II.

Explanation:

The correct order of events during meiosis is:

prophase I,

metaphase I,

anaphase I,

telophase I,

cytokinesis, and

meiosis II.

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Filed Under: Biology
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3 7758
Q:

What does one mole of H2O correspond to

A) 16 gms B) 18 gms
C) 20 gms D) 22 gms
 
Answer & Explanation Answer: B) 18 gms

Explanation:

The molar mass of H2O can be calculated as the following.

M(H2O)= [2 x M(H)] + [M(O)].

And we know that M(H) = 1g/mol, M(O) = 16g/mol.

So, M(H2O)= 2x1 + 16 = 18g/mol,

That means 1 mole of H2O contains 18g.

 

Hence, one mole of H2O corresponds to 18 grams.

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Filed Under: Chemistry
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6 7745
Q:

The respective ratio between the speed of a bike, a van  and lorry is 3 : 5 : 2. The speed of the van is 250 percent of the speed of the lorry which covers 360 km in 12 hours. What is the average speed of the bike and the van together?

A) 60 kmph B) 62 kmph
C) 64 kmph D) 63 kmph
 
Answer & Explanation Answer: A) 60 kmph

Explanation:

Speed of lorry = 36012 = 30 kmph

Speed of van =250100 x 30 = 75 kmph

Speed of bike = 35 x 75 = 45 kmph

Therefore, now required average speed of bike and van  = 75 + 452= 60 kmph.

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12 7743
Q:

K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ?

A) 6:00 am B) 6:30 pm
C) 5:45 am D) 5:52 pm
 
Answer & Explanation Answer: B) 6:30 pm

Explanation:

Suppose they meet after 'h' hours

Then

3h + 4h = 17.5

7h = 17.5

h = 2.5 hours

So they meet at => 4 + 2.5 = 6:30 pm

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12 7743
Q:

Given that 100.48 = x,  100.70 = y and xz = y2,  then the value of z is close to ___ ?

A) 3.7 B) 2.7
C) 3.6 D) 2.9
 
Answer & Explanation Answer: D) 2.9

Explanation:

xz = y2        10(0.48z) = 10(2 x 0.70) = 101.40

 0.48z = 1.40

 z = 140/18 = 35/12 = 2.9 (approx.)

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Filed Under: Simplification
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10 7740
Q:

Only genius can solve this puzzle?

genius_maths_puzzle1564054544.jpg image

A) 36 B) 40
C) 48 D) 60
 
Answer & Explanation Answer: C) 48

Explanation:

In the given puzzle the logic is

2 x 1 + 1 = 2 + 1 = 3

3 x 2 + 2 = 6 + 2 = 8

4 x 3 + 3 = 12 + 3 = 15

5 x 4 + 4 = 20 + 4 = 24

6 x 5 + 5 = 30 + 5 = 35

Similarly,

7 x 6 + 6 = 42 + 6 = 48

7 = 48.

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19 7731
Q:

If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ?

A) 40 kms B) 30 kms
C) 46 kms D) 32 kms
 
Answer & Explanation Answer: A) 40 kms

Explanation:

Let the actual distance travelled be x km.
Then x/8=(x+20)/12
=> 12x = 8x + 160
=> 4x = 160
=> x = 40 km.

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Filed Under: Time and Distance
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5 7730