Bank PO Questions and Answers with Explanation, Job Roles

Q:

Which of the following statements about monosaccharide structure is true?

A) Aldoses and ketoses differ in the position of their hydroxyl groups.	B) Monosaccharides can be classified according to the spatial arrangement of their atoms.
C) All monosaccharides contain carbon, hydrogen, oxygen, and nitrogen atoms.	D) A six-carbon sugar is called a pentose.

Answer & Explanation Answer: B) Monosaccharides can be classified according to the spatial arrangement of their atoms.

Explanation:

Monosaccharides, also called simple sugars, are the most basic units of carbohydrates. They are fundamental units of carbohydrates and cannot be further hydrolyzed to simpler compounds.

Hence, Monosaccharides can be classified according to the spatial arrangement of their atoms is true about Monosaccharides.

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Filed Under: Chemistry
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank PO

3 8237

Q:

A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?

A) 28 kmph	B) 24 kmph
C) 26 kmph	D) 32 kmph

Answer & Explanation Answer: B) 24 kmph

Explanation:

Total time taken = k/40 + 2k/20 hours

= 5k/40 = k/8 hours

Average speed = 3k/(k/8) = 24 kmph.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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6 8234

Q:

Find the C.I. on Rs. 15,225 for 9 months at 16% per annum compounded quarterly ?

A) Rs. 1911	B) Rs. 1909
C) Rs. 1901	D) Rs. 1907

Answer & Explanation Answer: C) Rs. 1901

Explanation:

P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.

Amount = $15225 x {(1 + \frac{4}{100})}^{3}$

= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05

=> C.I. = 17126 - 15625 = Rs. 1901.05.

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Filed Under: Compound Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

10 8230

Q:

K and L start the business, with L investing the total capital of Rs. 40,000 on the condition that K pays L interest @ 8% per annum on his half of the capital. L is a working partner and receives Rs.1200 per month from the total profit and any profit reamaining is equally shared by both of them. At the end of the year, it was found that the income of L is twice that of K. Find the total profit for the year ?

A) Rs.44000	B) Rs.46400
C) Rs.480800	D) Rs.46000

Answer & Explanation Answer: B) Rs.46400

Explanation:

Interest received by L from K = 8% of half of Rs.40,000

$\Rightarrow \frac{8}{100} \times 20000 = 1600$

Amount received by L per annum for being a working partner = 1200 x 12 = Rs.14,400

Let 'A' be the part of remaing profit that 'L' receives as his share.

Total income of 'K' = only his share from the reamaing profit

= 'A', as both share equally.

Given income of L = Twice the income of K

--> (1600 + 14400 + A ) = 2A

--> A= Rs.16000

Thus total profit = 2A + Rs.14,400= 2(16000) + 14400

= 32000 +14400 = Rs.46,400.

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Filed Under: Partnership
Exam Prep: CAT
Job Role: Bank PO

13 8228

Q:

In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ?

A) Quarter months	B) Half year
C) 2 years	D) 1 year

Answer & Explanation Answer: B) Half year

Explanation:

3300 ----- 3% ↑ (1st time interval, 99) → 3399.

Here, time interval is given as half-yearly i.e. 6 months.

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Filed Under: Compound Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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3 8227

Q:

I do just enough work to get by.

A) Disagree	B) Agree
C) Neutral	D) Strongly Disagree

Answer & Explanation Answer: A) Disagree

Explanation:

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Filed Under: English
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Job Role: Analyst , Bank Clerk , Bank PO

2 8226

Q:

The monomer of polythene is

A) ethylene	B) ethyl alcohol
C) vinyl chloride	D) ethanol

Answer & Explanation Answer: A) ethylene

Explanation:

The monomer of polythene is ethylene.

the_monomer_of_polythene_is1546857163.png image

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Filed Under: Chemistry
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Job Role: Analyst , Bank Clerk , Bank PO

17 8226

Q:

$i f \log \frac{a}{b} + \log \frac{b}{a} = \log (a + b), t h e n$

A) a + b = 1	B) a - b = 1
C) a = b	D) ab=1

Answer & Explanation Answer: A) a + b = 1

Explanation:

$i f \log \frac{a}{b} + \log \frac{b}{a} = \log (a + b), t h e n$

$\log (a + b) = \log (\frac{a}{b} \times \frac{b}{a}) = \log 1$

so, a+b=1

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

40 8226

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