Bank PO Questions and Answers with Explanation, Job Roles

Q:

Jaduguda mines are famous for

A) mica deposits	B) uranium deposits
C) gold deposits	D) iron ore

Answer & Explanation Answer: B) uranium deposits

Explanation:

The Jaduguda Mine also known as Jadugoda or Jadugora is a Uranium mine in Jaduguda village in the Purbi Singhbhum district of the Indian state of Jharkhand.

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Filed Under: Indian Geography
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

13 6825

Q:

Mr. X sold two properties P1 and P2 for Rs 1,00,000 each. He sold property P1 for 20% less than what he paid for it. What is the percentage of profit of property P2, so that he is not in gain or loss on the sale of two properties?

A) 33.33%	B) 29.97%
C) 25%	D) 22.22%

Answer & Explanation Answer: A) 33.33%

Explanation:

Let 'A' be the cost price of property P1.

Then from the given data, the selling price of P1 = Rs. 1,00,000

He got 20% loss on selling P1

$\Rightarrow A - \frac{20 A}{100} = 100000 \Rightarrow A = 1, 25, 000$

Therefore, the amount he lossed on selling P1 = 25,000

As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000

But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000

Hence, the profit percentage on P2 = $\frac{Gain}{CP} x 100 = \frac{25000}{75000} x 100 = \frac{100}{3} = 33.33 %$

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

10 6823

Q:

A man sold two flats for Rs. 4.15 lakhs each. On one he gained 2% and on the other he lost 2%. What percent is the effect of the sale on the whole ?

A) 0.25 %	B) 0.04 %
C) 0.5 %	D) 0 %

Answer & Explanation Answer: B) 0.04 %

Explanation:

In this type cases we always have loss only.

Loss% = ${(\frac{C o m m o n G a i n o r L o s s}{10})}^{2}$ = ${(\frac{2}{10})}^{2}$ = 1/25 = 0.04 %

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Filed Under: Profit and Loss
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

11 6823

Q:

The Value of $[\log (\tan (1^{0})) + \log (\tan (2^{0})) + \dots \dots + \log (\tan (89^{0}))]$ is

A) -1	B) 0
C) 1/2	D) 1

Answer & Explanation Answer: B) 0

Explanation:

$= [\log \tan (1^{0}) + \log \tan (89^{0})] + [\log \tan (2^{0}) + \log \tan (88^{0})] + \dots \dots + [\log \tan (45^{0})]$

$= \log [\tan (1^{0}) \times \tan (89^{0})] + \log [\tan (2^{0}) \times \tan (88^{0})] + \dots \dots + \log (1)$

$[∵ \tan (90 - θ) = c o t θ a n d \tan (45^{0}) = 1]$

= log 1 + log 1 +.....+log 1

= 0.

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Filed Under: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

27 6815

Q:

The bonds in the compound MgSO4 can be described as

A) covalent	B) ionic
C) both A & B	D) None of the above

Answer & Explanation Answer: C) both A & B

Explanation:

Here the given compound is MgSO4.

In the given compound, Sulphur (S) and Oxygen (O) are two non metals and Magnesium (Mg) is a metal.

In this compound, Sulphur and Oxygen reacts to form covalent bond and the metal Magnesium reacts with both non metals Sulphur and Oxygen to form ionic bonds.

Hence, in the given compound MgSO4 there are both covalent and ionic bonds.

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Filed Under: Chemistry
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

1 6813

Q:

Solve this logical Math puzzle?

logical_thinking_puzzle1536132282.jpg image

Answer

Let that something be 'x'

From the given data,

x + x/5 = 21

5x + x/5 = 21

6x = 21 x 5

=> x = 17.5

Hence, that something is x = 17.5.

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Subject: Math Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

9 6806

Q:

A train is moving and crossing a man who is running on a platform of 100 m at a speed of 8 kmph in the direction of the train, in 9 sec. If the speed of the train is 74 kmph. Find the length of the train ?

A) 202 mts	B) 188 mts
C) 165 mts	D) 156 mts

Answer & Explanation Answer: C) 165 mts

Explanation:

Let the length of the train = L mts

Relative speed of train and man = 74 - 8 = 66 kmph = 66 x 5/18 m/s

=> 66 x 5/18 = L/9

=> L = 165 mts.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

22 6805

Q:

A sum of Rs.1890 has to be used to give 9 prizes to the customers of a super market for their overall academic purchases. If each prize is Rs.30 less than its preceding price, what is the least value of the price ?

A) 90	B) 95
C) 85	D) 80

Answer & Explanation Answer: A) 90

Explanation:

Let the least value of the prize = Rs. x

Then the next value of the prize is x+30 , x+60, x+90, ....x+240.

Given total amount of cash prizes = Rs.1890

--> x + (x+30) + (x+60) + (x+90) + ....+ (x+240) = 1890

--> 9x + (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240) = 1890

--> 9x + 30(1 + 2 + 3 + 4....+ 8) = 1890

--> 9x + 30(36) = 1890

--> 9x = 810 --> x=90

Hence the least value of the prize x=90

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Filed Under: Mathematical Operations
Exam Prep: CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

29 6797

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