Bank PO Questions


Q:

Which of the following is not an aerosol?

A) mud B) dust
C) smoke D) fog
 
Answer & Explanation Answer: A) mud

Explanation:

Among the given options, mud is not an aerosol.

 

An aerosol is a suspension of fine solid particles or liquid droplets, in the air or another gas. Aerosols can be natural or anthropogenic. Examples of natural aerosols are fog, dust, forest exudates and geyser steam. Examples of anthropogenic aerosols are haze, particulate air pollutants, and smoke.

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Filed Under: Physics
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Q:

In a slip test, K got the 15th rank and he was 44th from the bottom of the list of passed students. 4 students did not take up the slip test and 3 students were failed. What is the total strenght of the class ?

A) 63 B) 62
C) 64 D) 65
 
Answer & Explanation Answer: D) 65

Explanation:

Total strength of the class is given by

15 + 44 + 4 + 3 - 1 = 65

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Filed Under: Simplification
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Q:

What percent is 120 of 85 ?

A) 133.33 % B) 141.17 %
C) 145.54 % D) 139.29 %
 
Answer & Explanation Answer: B) 141.17 %

Explanation:

Px85100=120

 

=> p = 12000/85 = 141.17 %

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Filed Under: Percentage
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Q:

Synonym for the word : Bleak

A) bare B) lush
C) warm D) verdant
 
Answer & Explanation Answer: A) bare

Explanation:

Bleak means an area of land lacking vegetation and exposed to the elements like deserts.

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Filed Under: Analogy
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Q:

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ?

A) 6/19 B) 3/10
C) 7/10 D) 6/17
 
Answer & Explanation Answer: B) 3/10

Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20
Let E = event of getting a multiple of 4 or 15
=multiples od 4 are {4, 8, 12, 16, 20}
And multiples of 15 means multiples of 3 and 5
= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.
= the common multiple is only (15).
=> E = n(E)= 6
Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.

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Filed Under: Probability
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Q:

Which reaction occurs spontaneously?

A) Cl2(g) + 2NaF(aq)--> F2(g) + 2NaCl(aq) B) I2(s) + 2NaF(aq)--> F2(g) + 2NaI(aq)
C) Cl2(g) + 2NaBr(aq)-->Br2(l) + 2NaCl(aq) D) I2(s) + 2NaBr(aq)--> Br2(l) + 2NaI(aq)
 
Answer & Explanation Answer: C) Cl2(g) + 2NaBr(aq)-->Br2(l) + 2NaCl(aq)

Explanation:

In this chemical reaction chlorine change oxidation number from 0 to -1 (reduction) and bromine change oxidation number from -1 to 0 (oxidation).

Chlorine is stronger oxidation reagent than bromine.

In VIIA or group 17 (halogen elements) there are six elements: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At) and tennessin(Ts).

They have high electronegativity because they have seven valence electrons in their outermost energy level, so they can gain an electron to have the octet rule.  

Going down in the group, element are weaker oxidazing reagent and less reactive.

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Filed Under: Chemistry
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2 4859
Q:

In what way does ocean water move globally?

A) Along cold water currents from the equator to the poles. B) Along warm water currents from the warmer regions to colder regions
C) Along warm water currents from the equator to the poles D) None of the above
 
Answer & Explanation Answer: C) Along warm water currents from the equator to the poles

Explanation:
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Filed Under: World Geography
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4 4859
Q:

Kramer borrowed $4000 from George at an interest rate of 7% compounded semiannually. The loan is to be repaid by three payments. The first payment, $1000, is due two years after the date of the loan. The second and third payments are due three and five years, respectively, after the initial loan. Calculate the amounts of the second and third payments if the second payment is to be twice the size of the third payment.

A) 1389 B) 1359
C) 1379 D) 1339.33
 
Answer & Explanation Answer: D) 1339.33

Explanation:

Given:j=7% compounded semiannually making m=2 and i = j/m= 7%/2 = 3.5%
Let x represent the third payment. Then the second payment must be 2x.
PV1,PV2, andPV3 represent the present values of the first, second, and third payments.

Since the sum of the present values of all payments equals the original loan, then
PV1 + PV2  +PV3  =$4000 -------(1)

PV1   =FV/(1 + i)^n  =$1000/(1.035)^4=  $871.44

At first, we may be stumped as to how to proceed for
PV2 and PV3. Let’s think about the third payment of x dollars. We can compute the present value of just $1 from the x dollars

pv=1/(1.035)^10=0.7089188

PV2   =2x * 0.7089188 = 1.6270013x
PV3   =x * 0.7089188=0.7089188x
Now substitute these values into equation ➀ and solve for x.
$871.442 + 1.6270013x + 0.7089188x  =$4000

2.3359201x  =$3128.558

x=$1339.326
Kramer’s second payment will be 2($1339.326)  =$2678.65, and the third payment will be $1339.33

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Filed Under: Compound Interest
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