Bank PO Questions

The given number series follows a pattern that

11

11 - 5.5 = 5.5

5.5 + 4.5 = 10

10 - 3.5 = 6.5

6.5 + 2.5 = 9

9 - 1.5 = 7.5

Hence, the next number in the given number series is 7.5.

The given number series 8, 18, 56, 232, 1165 

8

8 x 2 + 2 = 18

18 x 3 + 3 = 57 (not 56)

57 x 4 + 4 = 232

232 x 5 + 5 = 1165

Hence, the odd man in the given series is 56.

The nationalisation of banks in India took place in 1969 by Mrs. Indira Gandhi the then prime minister. It nationalised 14 banks then. These banks were mostly owned by businessmen and even managed by them. Before the steps of nationalisation of Indian banks, only State Bank of India (SBI) was nationalised. It took place in July 1955 under the SBI Act of 1955.

Nationalisation of Seven State Banks of India (formed subsidiary) took place on 19th July, 1960.

1955 : Nationalisation of State Bank of India.
1969 : Nationalisation of 14 major banks.
1980 : Nationalisation of seven banks with deposits over 200 crores.

The given number series is 3, 5, 13, 43, 167

3

3 x 1 + 2 = 5

5 x 2 + 3 = 13

13 x 3 + 4 = 43

43 x 4 + 5 = 177 (not equal to 167)

Hence, the odd number in the given number sequence is 167. 

The sum of square of two no is 116 i.e no lie 1-11, because 11x11 =121 which is greater than 116
again after cheaking all possible pair of no only 4 and 10 satisfy this condsn , again the progression is of positive integer so 10 cant not be 1st term
so the 1st term is 4,
but from the 2nd we cant able to find the 1st term

so only 1st statement is sufficient to answer the question

Let original length = x and original breadth = y.

Original area = xy. 

New length = x/2 and New breadth=3y 

New area = 32xy 

Therefore,  Increase in area = New area-original area = 32xy-xy=12xy 

Therefore,  Increase % = increase in area original area*100=12xyxy*100=50 %

IG stands for Inspector General of Police. DIG(Deputy Inspector General ofPolice) is a One-star rank in the police service who works under IG.

let ABCD be the given parallelogram 

area of parallelogram ABCD = 2 x (area of triangle ABC) 

now a = 30m, b = 14m and c = 40m

 s=1/2 x (30+14+40) = 42 

Area of triangle ABC = ss-as-bs-c  

= 4212282= 168sq m 

area of parallelogram ABCD = 2 x 168 = 336 sq m