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Q:

Please enter the Missing number: 4 8 14 22 ?

A) 28 B) 32
C) 46 D) 36
 
Answer & Explanation Answer: B) 32

Explanation:

Here the given series follows a pattern that,

22 - 0 = 4  

32 - 1 = 8  

42 - 2 = 14

52 - 3 = 22

62 - 4 = 32

Hence, the missing number is 32

 

 

Method 2 ::

The difference between 4 and 8 is 4, the difference between 8 and 14 is 6, the difference between 14 and 22 is 8. So the next difference between 22 and the next number will be 10 since it follows (4,6,8,10 - add +2 each time)

Hence, 22 + 10 = 32 is the missing number.

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Filed Under: Odd Man Out
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8 7923
Q:

If a soldier fires 7 shots from a gun in 12 minutes then find the total number of shots fired by the man in 3/2 hrs.

A) 45 B) 44
C) 46 D) 47
 
Answer & Explanation Answer: C) 46

Explanation:

Here given soldier shots 7 shots in 12 min

=> 1 shot doen't take any time in 12 min 

=> Only 6 shots take 12 min 

12 min ------ 6 shots 

90 min ------ ? shots 

=> 90 x (6/12) = 45 

Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.

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Filed Under: Time and Work
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11 7794
Q:

What is the gram formula mass of Li2SO4?

A) 101.2487 B) 109.9446
C) 111.2687 D) 106.5871
 
Answer & Explanation Answer: B) 109.9446

Explanation:

The term gram formula mass is synonymous with molecular mass. So, to get this, we must add molar mass of all the elements in this compound.

 

Given compound is Lithium Sulphate - Li2SO4

Elemental calculation ::

Li  -  Lithium   -   6.941    -     2   -   13.88200 %
S  -  Sulfur     -    32.065   -    1   -   32.065 %
O  -  Oxygen   -   15.9994  -    4   -   63.9976 %

Now, total = 12.6264 + 29.1647 + 58.2090 = 109.9446 

 

Hence, the gram formula mass of Li2SO4 = 109.9446.

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Filed Under: Chemistry
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4 7764
Q:

Ajay who is a King, at his eleventh hour, called his three queens and distributed his gold in the following way: He gave 50% of his wealth to his first wife, 50% of the rest to his second wife and again 50% of the rest to his third wife. If their combined share is worth1,30,900 kilograms of gold, find the quantity of gold King Ajay was having initially?

A) 153145 kgs B) 147890 kgs
C) 152400 kgs D) 149600 kgs
 
Answer & Explanation Answer: D) 149600 kgs

Explanation:

Let the total quantity of gold be p kgs.

According to the question,

50% of p + 25% of p + 12.5% of p = 130900

87.5% of p = 130900

p = 130900 x 100/87.5  = 149600 kgs.

 

Therefore, the initial gold quantity that king has = p = 149600 kgs.

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Filed Under: Percentage
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7 7682
Q:

64 S on CB?

Answer

The given statement implies that 64 Squares on Carrom Board.

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Subject: Logic Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
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14 7613
Q:

Two letters are randomly chosen from the word TIME. Find the probability that the letters are T and M?

A) 1/4 B) 1/6
C) 1/8 D) 4
 
Answer & Explanation Answer: B) 1/6

Explanation:

Required probability is given by P(E) = n(E)n(S) = 14C2 = 16

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Filed Under: Probability
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20 7595
Q:

It is necessary to sort a file before searching a particular item 

A) True B) False
C) May or may not be true D) None of the above
 
Answer & Explanation Answer: C) May or may not be true

Explanation:

If less work is involved in searching a element than to sort and then extract, then we don’t go for sort

If frequent use of the file is required for the purpose of retrieving specific element, it is more efficient to sort the file.

Thus it depends on situation

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Filed Under: Database
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2 7587
Q:

A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained?

A) 1/5 B) 1/6
C) 1/7 D) 1/8
 
Answer & Explanation Answer: B) 1/6

Explanation:

Total work is given by L.C.M of 72, 48, 36

Total work = 144 units

Efficieny of A = 144/72 = 2 units/day

Efficieny of B = 144/48 = 3 units/day

Efficieny of C = 144/36 = 4 units/day

 

According to the given data,

2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100

3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54

p = 198/16.5

p = 12 days.

 

Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day

(C+D) in p days = (4 + 6) x 12 = 120 unit

Remained part of work = (144-120)/144 = 1/6.

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Filed Under: Time and Work
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7 7558