IT Trainer Questions

Sri Ramakrishna is called as the Prophet of New India.

Sri Ramakrishna (1836-86) mostly known as Ramakrishna Paramhamsa was a spiritual genius now respected in India and abroad as an outstanding saint of our times. His life and thoughts represents the highest and best of modern Hindu philosophy and practice.

Reverence and admiration for him amongst Bengali elites led to the formation of the Ramakrishna Mission by his chief disciple Swami Vivekananda. His devotees look upon him as an incarnation or Avatara of the formless Supreme Brahman as described in the Vedanta while some devotees see him as an avatara of Vishnu.

Food is processed by the stomach to provide energy for the functioning of the body.
Similarly, fuel is processed by the engine to provide energy for the functioning of automobile.

Given that If Theresa's daughter is my daughter's mother

It has 2 ways of Answers such that it depends on the sex of me. That is Male or Female.

1) If I am a Male :

My daughter's mother is my wife.

My wife is Teresa's daughter

=> I am Teresa's Son-in-law.

2) If I am a Female :

My daughter's mother is myself.

Myself Teresa's daughter.

=> I am Teresa's Daughter.

But in the given options only Son-in-law is available and daughter is not given.

So, Son-in-law is correct.

The smallest unit of data storage in a computer is called Bit (Binary Digit). Half a byte (four bits) is called a Nibble.

1 bit (binary digit) = the value of 0 or 1

8 bits = 1 byte

1024 bytes = 1 kilobyte

1024 kilobytes = 1 megabyte

1024 megabytes = 1 gigabyte

1024 gigabytes = 1 terabyte

1024 terabytes = 1 petabyte

Hence, Computer storage units smallest to largest i.e, in ascending order is

 1 bit  <  1 byte  <  1 KB  <  1 MB  <  1 GB  <  1TB  <  1 PB.

In computing, the expansion card or board or accessory card is a printed circuit board that can be inserted into an electrical connector or expansion slot, on a computer motherboard, to add functionality to a computer system via the expansion bus.

Let work done by 1 man in i day be m

and Let work done by 1 boy in 1 day be b

From the given data,

4(5m + 3b) = 23

20m + 12b = 23....(1)

2(3m + 2b) = 7

6m + 4b = 7 ....(2)

By solving (1) & (2), we get

m = 1, b = 1/4

Let the number of required boys = n

6(7 1 + n x 1/4) = 45

=> n = 2.