Questions

Q:

Though the countries of South - West Asia have abundant power resources, they have not developed major industries mainly because

A) They do not have raw materials B) They do not have a large market
C) They do not have skilled labour D) They do not have capital
 
Answer & Explanation Answer: A) They do not have raw materials

Explanation:
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Filed Under: World Geography

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Q:

Uranus takes _______years to orbit the sun

A) 48 B) 84
C) 50 D) 60
 
Answer & Explanation Answer: B) 84

Explanation:

Uranus is 2,870 million kilometers away from the sun and the time taken to complete one round at a speed of 6.8 km/sec is as  long as 84 years on earth

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Filed Under: World Geography

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Q:

Who was Shivaji’s Guru?

A) Eknath B) Tukaram
C) Dnyanesh D) Samartha Ramadas
 
Answer & Explanation Answer: D) Samartha Ramadas

Explanation:

Shivaji’s Guru was Shree Samarth Ramdas was a noted 17th-century saint and spiritual poet of Maharashtra. He is most remembered for his Advaita Vedantist text, the Dasbodh. Ramdas was a devotee of Hanuman and Rama.

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Filed Under: Indian History
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

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Q:

What is a property of most metals?

A) Conductivity B) Malleability
C) Luster D) All of the above
 
Answer & Explanation Answer: D) All of the above

Explanation:

We know that most of the metals are goof conductors of electricity and heat. Metals are very strong but they are malleable i.e, they can be bent into a shape. These are shiny when they are cut or polished. 

 

Hence, metals are malleable, conductors and luster. All the above are properties of the metals.

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Filed Under: Physics
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

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Q:

Who has the power to expel senators from office?

Answer

House of representatives has the power of impeachment in the office.

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Subject: Indian Politics Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

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Q:

Which type of bond is found in sodium bromide?

A) Ionic B) Covalent
C) Polar covalent D) None of the above
 
Answer & Explanation Answer: A) Ionic

Explanation:
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Filed Under: Chemistry
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Q:

In the given question, a part of the sentence is printed in bold. Below the sentence, three alternatives to the bold part are given which may help improve the sentence. Choose the option that reflects the correct use of the phrase in the context of the sentence. In case the given sentence is correct, your answer is (E) i.e. No correction required.

Although I don’t have any special bond with the rank and folder of the Labour Union, I know some top engineers.

(i) in the rank and folders of the Labour Union

(ii) with the rank and portfolio of the Labour Union

(iii) with the rank and file of the Labour Union

A) Only (i) B) Only (ii)
C) Only (iii) D) (i) and (ii)
 
Answer & Explanation Answer: C) Only (iii)

Explanation:
The correct phrase is ‘rank and file’ which means ‘the ordinary members of an organization’.
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Filed Under: English

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Q:

Write a c program for merge sort.

Answer

#include
#define MAX 50

void mergeSort(int arr[],int low,int mid,int high);
void partition(int arr[],int low,int high);

int main(){
  
    int merge[MAX],i,n;

    printf("Enter the total number of elements: ");
    scanf("%d",&n);

    printf("Enter the elements which to be sort: ");
    for(i=0;i<n;i++){
         scanf("%d",&merge[i]);
    }

    partition(merge,0,n-1);

    printf("After merge sorting elements are: ");
    for(i=0;i<n;i++){
         printf("%d ",merge[i]);
    }

   return 0;
}

void partition(int arr[],int low,int high){

    int mid;

    if(low<high){
         mid=(low+high)/2;
         partition(arr,low,mid);
         partition(arr,mid+1,high);
         mergeSort(arr,low,mid,high);
    }
}

void mergeSort(int arr[],int low,int mid,int high){

    int i,m,k,l,temp[MAX];

    l=low;
    i=low;
    m=mid+1;

    while((l<=mid)&&(m<=high)){

         if(arr[l]<=arr[m]){
             temp[i]=arr[l];
             l++;
         }
         else{
             temp[i]=arr[m];
             m++;
         }
         i++;
    }

    if(l>mid){
         for(k=m;k<=high;k++){
             temp[i]=arr[k];
             i++;
         }
    }
    else{
         for(k=l;k<=mid;k++){
             temp[i]=arr[k];
             i++;
         }
    }
  
    for(k=low;k<=high;k++){
         arr[k]=temp[k];
    }
}


Sample output:

Enter the total number of elements: 5
Enter the elements which to be sort: 2 5 0 9 1
After merge sorting elements are: 0 1 2 5 9

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Subject: Programming

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