A) 28 | B) 29 |

C) 31 | D) 35 |

Explanation:

Clearly, we have :

A = B - 3 ...(i)

D + 5 = E ...(ii)

A+C = 2E ...(iii)

B + D = A+C = 2E ...(iv)

A+B + C + D + E=150 ...(v)

From (iii), (iv) and (v), we get: 5E = 150 or E = 30.

Putting E = 30 in (ii), we get: D = 25.

Putting E = 30 and D = 25 in (iv), we get: B = 35.

Putting B = 35 in (i), we get: A = 32.

Putting A = 32 and E = 30 in (iii), we get: C = 28.

A) 933 | B) 872 |

C) 749 | D) 653 |

Explanation:

From the given data,

**Largest number = 974**

Therefore, the required number is **749.**

A) 1 | B) 2 |

C) 3 | D) 4 |

Explanation:

Given two lines are parallel

pa+b=2

b=-pa+2..........(1)

3a+b=4

b=-3a+4 ...........(2)

m_{1} = -p

m_{2}= -3

The condition for the two lines to be parallel is **m _{1}=m_{2}**

p = 3

A) 0 | B) 1 |

C) 2 | D) 3 |

A) 110 | B) 90 |

C) 100 | D) 180 |

Explanation:

Let number of 2 wheelers be 'x'

and 4 wheelers be 'y'

Given total number of vehicles = 200

i.e, x + y = 200 ....(1)

Given total number of wheels = 580

i.e, 2x + 4y = 580 ...(2)

By solving (1)&(2), we get

y = 90

=> x = 110

Therefore, number of two wheelers = 110

number of four wheelers = 90

A) 9, 0, 3 | B) 1, 3, 8 |

C) 7, 0, 1 | D) 2, 4, 1 |

Explanation:

0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |

0 | 1 | 4 | 8 | 2 | 6 | 5 | 7 | 3 | 9 |

Here pairs interchanged are

2, 4

3, 8

5, 6

Unchanged are 0, 1, 7, 9