49
Q:

# If you write down all the numbers from 1 to 100, then how many times do you write 3 ?

 A) 11 B) 18 C) 20 D) 21

Explanation:

Clearly, From 1 to 100, there are ten numbers with 3 as the unit's digit - 3, 13, 23, 33, 43, 53, 63, 73, 83, 93 and ten numbers with 3 as the ten's digit - 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.

So, required number = 10 + 10 = 20.

Q:

A Child has 1200 five rupee coins. He wants to place them in such a way that the number of rows and the number of columns remains the same. What is the minimum number of coins that he needs more for this purpose?

 A) 125 B) 96 C) 35 D) 25

Explanation:

We know that, to be in the form that the number of rows and the number of columns to be equal the number should be a perfect square ($a^{2}$).
Given number is 1200
The perfect number which is above and near to 1200 is 1225 which is 35 $\times$ 35.
$\therefore$ The minimum number of coins he need is 25.

10 48
Q:

In a note collection, there is one new Rs.2000 note for every three old Rs.500 notes. 10 more new Rs.2000 notes are added to the collection and the ratio of new Rs.2000 notes to old Rs.500 notes would be 1: 2. Based on the information, the total number of notes in the collection now becomes?

 A) 60 B) 30 C) 70 D) 90

Explanation:

Let 'x' be the number of new Rs.2000 notes.
Given for one new 2000 note there are three old 500 notes.
$\fn_jvn&space;\small&space;\Rightarrow$ 3x
Given 10 more new Rs.2000 notes are added to the collection
and the ratio of new Rs.2000 notes to old Rs.500 notes
$\fn_jvn&space;\small&space;\Rightarrow$ $\inline \fn_jvn \small \frac{x+10}{3x}=\frac{1}{2} \Rightarrow x=20$
Therefore, number of new Rs.2000 notes $\fn_jvn&space;\small&space;\Rightarrow$  x+10 = 30.
old Rs.500 notes $\fn_jvn&space;\small&space;\Rightarrow$ 3x = 60.
Thus, the total number of notes in the collection $\fn_jvn&space;\small&space;\Rightarrow$  30 + 60 = 90.

8 77
Q:

In a certain office, $\inline \frac{1}{3}$ of workers are women, $\inline \frac{1}{2}$of the women are married and $\inline \frac{1}{3}$ of the married women have children. If $\inline \frac{3}{4}$ of the men are married and $\inline \frac{2}{3}$ of the married men have children, what part of the workers are without children ?

 A) 5/18 B) 4/9 C) 11/18 D) 17/36

Explanation:

Let the total number of workers be x. Then,

Number of women = $\inline \frac{x}{3}$ and number of men = $\inline \left ( x-\frac{x}{3} \right )$ = $\inline \frac{2x}{3}$

Number of women having children = $\inline \fn_jvn \frac{1}{3}\;of\; \frac{1}{2}\; of\; \frac{x}{3}=\frac{x}{18}$

Number of men having children = $\inline \fn_jvn \frac{2}{3}\;of\; \frac{3}{4}\; of\; \frac{2x}{3}=\frac{x}{3}$

Number of workers having children = $\inline \fn_jvn \left ( \frac{x}{18}+\frac{x}{3} \right )=\frac{7x}{18}$

$\inline \fn_jvn \therefore$ workers having no children = $\inline \fn_jvn \left ( x-\frac{7x}{18} \right )=\frac{11x}{18}=\frac{11}{18}$ of all workers

15 292
Q:

The following question is based on the given data for an examination.

A. Candidates appeared                 10500

B. Passed in all the five subjects     5685

C. Passed in three subjects only     1498

D. Passed in two subjects only       1250

E. Passed in one subject only           835

F. Failed in English only                       78

G. Failed in Maths only                      275

H. Failed in Physics only                    149

I. Failed in Chemistry only                147

J. Failed in Biology only                     221

How many candidates passed in at least four subjects ?

 A) 6555 B) 5685 C) 1705 D) 870

Explanation:

Candidates passed in atleast four subjects

= (Candidates passed in 4 subjects) + (Candidates Passed in all 5 subjects)

= (Candidates failed in only 1 subject ) + ( Candidates passed in all subjects)

= (78 + 275 + 149 + 147 + 221) + 5685 = 870 + 5685 = 6555

11 838
Q:

A man has a certain number of small boxes to pack into parcles. If he packs 3, 4, 5 or 6 in a parcel, he is left with one over; if he packs 7 in a parcle, none is left over. What is the number of boxes, he may have to pack?

 A) 106 B) 301 C) 309 D) 400