A) 20 | B) 25 |

C) 30 | D) Data inadequate |

Explanation:

Let the number of boys and girls participating in sports be 3x and 2x respectively.

Then, 3x = 15 or x = 5.

So, number of girls participating in sports = 2x = 10.

Number of students not participating in sports = 60 - (15 + 10) = 35.

Let number of boys not participating in sports be y.

Then, number of girls not participating in sports = (35 -y).

Therefore (35 - y) = y + 5 2y 30 y = 15.

So, number of girls not participating in sports = (35 - 15) = 20.

Hence, total number of girls in the class = (10 + 20) = 30.

A) 933 | B) 872 |

C) 749 | D) 653 |

Explanation:

From the given data,

**Largest number = 974**

Therefore, the required number is **749.**

A) 1 | B) 2 |

C) 3 | D) 4 |

Explanation:

Given two lines are parallel

pa+b=2

b=-pa+2..........(1)

3a+b=4

b=-3a+4 ...........(2)

m_{1} = -p

m_{2}= -3

The condition for the two lines to be parallel is **m _{1}=m_{2}**

p = 3

A) 0 | B) 1 |

C) 2 | D) 3 |

A) 110 | B) 90 |

C) 100 | D) 180 |

Explanation:

Let number of 2 wheelers be 'x'

and 4 wheelers be 'y'

Given total number of vehicles = 200

i.e, x + y = 200 ....(1)

Given total number of wheels = 580

i.e, 2x + 4y = 580 ...(2)

By solving (1)&(2), we get

y = 90

=> x = 110

Therefore, number of two wheelers = 110

number of four wheelers = 90

A) 9, 0, 3 | B) 1, 3, 8 |

C) 7, 0, 1 | D) 2, 4, 1 |

Explanation:

0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |

0 | 1 | 4 | 8 | 2 | 6 | 5 | 7 | 3 | 9 |

Here pairs interchanged are

2, 4

3, 8

5, 6

Unchanged are 0, 1, 7, 9