A) 18 | B) 36 |

C) 45 | D) None of these |

Explanation:

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then,

R + G + B = 108 ...(i),

G + R = 2B ...(ii)

B = 2R ...(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

A) 933 | B) 872 |

C) 749 | D) 653 |

Explanation:

From the given data,

**Largest number = 974**

Therefore, the required number is **749.**

A) 1 | B) 2 |

C) 3 | D) 4 |

Explanation:

Given two lines are parallel

pa+b=2

b=-pa+2..........(1)

3a+b=4

b=-3a+4 ...........(2)

m_{1} = -p

m_{2}= -3

The condition for the two lines to be parallel is **m _{1}=m_{2}**

p = 3

A) 0 | B) 1 |

C) 2 | D) 3 |

A) 110 | B) 90 |

C) 100 | D) 180 |

Explanation:

Let number of 2 wheelers be 'x'

and 4 wheelers be 'y'

Given total number of vehicles = 200

i.e, x + y = 200 ....(1)

Given total number of wheels = 580

i.e, 2x + 4y = 580 ...(2)

By solving (1)&(2), we get

y = 90

=> x = 110

Therefore, number of two wheelers = 110

number of four wheelers = 90

A) 9, 0, 3 | B) 1, 3, 8 |

C) 7, 0, 1 | D) 2, 4, 1 |

Explanation:

0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |

0 | 1 | 4 | 8 | 2 | 6 | 5 | 7 | 3 | 9 |

Here pairs interchanged are

2, 4

3, 8

5, 6

Unchanged are 0, 1, 7, 9