15
Q:

# A sum of Rs.1890 has to be used to give 9 prizes to the customers of a super market for their overall academic purchases. If each prize is Rs.30 less than its preceding price, what is the least value of the price ?

 A) 90 B) 95 C) 85 D) 80

Explanation:

Let the least value of the prize = Rs. x

Then the next value of the prize is x+30 , x+60, x+90, ....x+240.

Given total amount of cash prizes = Rs.1890

--> x + (x+30) + (x+60) + (x+90) + ....+ (x+240) = 1890

--> 9x + (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240) = 1890

--> 9x + 30(1 + 2 + 3 + 4....+ 8) = 1890

--> 9x + 30(36) = 1890

--> 9x = 810 --> x=90

Hence the least value of the prize x=90

Q:

5x - 6 = 3x - 8

Solve the above equation.

 A) 2 B) -1 C) -2 D) 1

Explanation:

Given 5x - 6 = 3x - 8

5x - 3x = -8 + 6

2x = -2

=> x = -1.

0 99
Q:

3 x 3 + 3 - 3 + 3 = ?

 A) 9 B) 12 C) -3 D) 3

Explanation:

Using BODMAS law,

3 x 3 + 3 - 3 + 3 =

3 x 3 = 12

= 12 + 3 - 3 + 3

=  9 + 3

= 12

Hence, 3 x 3 + 3 - 3 + 3 = 12.

1 132
Q:

What is x squared plus x squared?

 A) 4x B) 2x^2 C) x^4 D) 2x

Explanation:

In an algebraic expression, like terms are terms that contain the same variables raised to the same powers. Calculating x-squared plus x-squared is a matter of combining like terms.

Now x^2 + x^2 = 2x^2

Hence, x-squared plus x-squared is equal to 2 times x squared.

1 126
Q:

What is

 A) 0 B) 42 C) 50 D) 57

Explanation:

Given 7 + 7/7 + 7 x 7 - 7

By using BODMAS rule,

7 + 1 + 7 x 7 - 7

= 8 + 49 - 7

= 57 - 7

= 50.

Hence 7 + 7/7 + 7 x 7 - 7 = 50.

1 398
Q:

Find the Value of ?

 A) 81 B) 77 C) 73 D) 89

Explanation:

This can be done in a method called Approximation.

Now,

6 379
Q:

Can you Solve  =

 A) 112 B) 56 C) 0 D) 98

Explanation:

8 352
Q:

The last two digits of ${\mathbf{2151}}^{\mathbf{415}}$?

 A) 81 B) 61 C) 91 D) 51

Explanation:

Unit digit of this expression is always 1 as the base ends with 1.

For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.

i.e, tenth place digit in 2151 is 5 and

tenth place digit in power 415 is 1

And the units digit in the product of 5 x 1 = 5

Therefore, last two digits of ${\mathbf{2151}}^{\mathbf{415}}$ is 51.

7 579
Q:

What is the value of P in the following Equation ?

 A) 3.9 B) 4.1 C) 3.7 D) 4.5

Explanation:

Given equation is

Here it is in the form of

Here m = 2.5 , n = p, m+n = 7

=> 2.5 + p = 7

=> p = 7 - 2.5

=> p = 4.5