A) 8 | B) 4 |

C) 2 | D) -1 |

Explanation:

By the given data, we have the expression :

(3 × 15 + 19) ÷ 8 - 6 = (45 + 19) ÷ 8 - 6 = 64 ÷ 8 - 6 = 8 - 6 = 2

A) A | B) B |

C) C | D) D |

Explanation:

The quadratic equation whose roots are reciprocal of can be obtained by replacing x by 1/x.

Hence, 2 + 5(1/x) + 3 = 0

=>

A) 1 7/12 | B) 1 5/12 |

C) 3 7/12 | D) 3 1/12 |

Explanation:

? = (3 + 4 - 2 - 1) + ( 1/6 + 1/2 - 2/3 - 11/12)

= 4 + ((2+6-8-11)/12)

= 4 - 11/12 = 3 1/12.

A) 20 | B) 29 |

C) 28 | D) 24 |

Explanation:

Let the runs scored by P, Q, R, S and T be a, b, c, d and e

From given data,

a + b + c + d + e = 36 x 5 = 180

b + c = 107

Let a = x

e = x-8

d = x-3

now 3x - 11 + 107 = 180

3x = 84

x = 28

e's score = 28-8 = 20

A) 10 | B) 6 |

C) 12 | D) 0 |

Explanation:

-4-(-10) = -4+10 = 6

-10-(-4) = -10+4= -6

6-(-6) = 6+6 = 12

A) 90 | B) 95 |

C) 85 | D) 80 |

Explanation:

Let the least value of the prize = Rs. x

Then the next value of the prize is x+30 , x+60, x+90, ....x+240.

Given total amount of cash prizes = Rs.1890

x + (x+30) + (x+60) + (x+90) + ....+ (x+240) = 1890

9x + (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240) = 1890

9x + 30(1 + 2 + 3 + 4....+ 8) = 1890

9x + 30(36) = 1890

9x = 810 x=90

Hence the least value of the prize x=90