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Q:

Weight of Arun is 4/7 of the weight of Bablu. Weight of Bablu is 1/2 of the weight of Ram. Weight of Ram is 4 times of the weight of Deep. Weight of Deepis 1/9 of the weight of Ankit. Whose weight is more than the weight of Deep but less than the weight of Bablu?

A) Ankit	B) Arun
C) Ram	D) Deep

Answer & Explanation Answer: B) Arun

Explanation:

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Filed Under: Arithmetical Reasoning
Exam Prep: Bank Exams

Q:

P, Q and R are partners in a company. In any year P receives 1/9 part of profit, Q receives 1/6 part of profit and R receives Rs 130000. How much amount (in Rs) will P get as profit?

A) 40000	B) 36000
C) 18000	D) 20000

Answer & Explanation Answer: D) 20000

Explanation:

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

Q:

Of the 3 numbers whose average is 70, the first is 1/9 times the sum of other 2. The first number is

A) 32	B) 21
C) 14	D) 42

Answer & Explanation Answer: B) 21

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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

Q:

The marked price of an article is Rs. 5000. But due to a special festive offer a certain percent of discount is declared. Mr. X availed this oppurtunity and bought the article at reduced price. He then sold it at Rs. 5000 and thereby made a profit of 11 1/9%. The percentage of discount allowed was?

A) 10	B) 10/3
C) 15/2	D) 100/9

Answer & Explanation Answer: A) 10

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Filed Under: Percentage
Exam Prep: Bank Exams

Q:

A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.

1, 0.25, 1/9, ? , 0.04, 1/36

A) 0.0625	B) 0.025
C) 1/8	D) 1/6

Answer & Explanation Answer: A) 0.0625

Explanation:

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Filed Under: Number Series
Exam Prep: Bank Exams

Q:

Weight of C is twice the weight of M. Weight of M is 1/9 of the weight of R. Weight of R is 5/2 of the weight of K. Weight of K is 1/3 of the weight of G. Who is the second lightest?

A) C	B) M
C) K	D) G

Answer & Explanation Answer: A) C

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Filed Under: Arithmetical Reasoning
Exam Prep: Bank Exams

Q:

A box contains 5 green, 4 yellow and 5 white pearls. Four pearls are drawn at random. What is the probability that they are not of the same colour ?

A) 11/91

B) 4/11

C) 1/11

D) 90/91

A) Option A	B) Option B
C) Option C	D) Option D

Answer & Explanation Answer: D) Option D

Explanation:

Let S be the sample space. Then,
n(s) = number of ways of drawing 4 pearls out of 14

= $C_{4}^{14}$ ways = $\frac{14 \times 13 \times 12 \times 11}{4 \times 3 \times 2 \times 1}$ = 1001

Let E be the event of drawing 4 pearls of the same colour.
Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5)

$\Rightarrow C_{1}^{5} + C_{4}^{4} + C_{1}^{5}$ = 5+1+5 =11

P(E) = $\frac{n (E)}{n (S)} = \frac{11}{1001} = \frac{1}{91}$

Required probability = $1 - \frac{1}{91} = \frac{90}{91}$

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

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