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Q:

11M13, 13Q17, ? , 17V22 , 19W23

A) 15U21 B) 15R18
C) 15S19 D) 15T20
 
Answer & Explanation Answer: D) 15T20

Explanation:

In the given series

 

1st term has odd number starting from 11, So the Series is 11, 13, 15, 17, 19 

 

2nd term has an alphabet follwed by its alpha numeric number in the order +4, +3, +2, +1. So  the Series is M13, Q17, T20, V22, W23

 

Therefore, 15T20 is the answer.

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Filed Under: Number Series

Q:

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You are the administrator of network X. You decided to implement RIP in the following topology (click exhibit). You do not want R3 to receive RIP updates. What configuration changes need to be implemented?

A) Implement a passive-interface on R1 B) Nothing needs to be configured
C) Create a sub-interface on R1 D) Change the routing protocol to OSPF
 
Answer & Explanation Answer: A) Implement a passive-interface on R1

Explanation:

Explanation: To block RIP broadcasts on an interface connected to a subnet of a RIP-enabled network add the passive-interface command to the RIP Process

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Filed Under: CCENT

Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. Q1F, S2E, U6D, W21C, ?

A) Z88B B) Y88B
C) Y44B D) K25P
 
Answer & Explanation Answer: B) Y88B

Explanation:

The first letter moves two steps forward. The last letter moves one steps backward. The number series runs as follows :
1 x 1 + 1 = 2
2 x 2 + 2 = 6
6 x 3 + 3 = 21
21 x 4 + 4 = 88.

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Filed Under: Number Series