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Q:

From a deck of 52 cards, a 5 card hand is dealt.How many distinct hands can be formed if there are atleast 2 queens?

A) 103336	B) 120000
C) 108336	D) 108333

Answer & Explanation Answer: C) 108336

Explanation:

The total possible cases would be a 5 card hand with no restrictions : $52 C_{5}$ 5

The unwanted cases are:

no queens(out of 48 non-queens cards we get 5) $48 C_{5}$

only 1 queen(out of 4 queens we get 1,and out of 48 non-queens we get 4) $4 C_{1} * 48 C_{4}$

Therefore, $52 C_{5} - (48 C_{5} + 4 C_{1} * 48 C_{4}) = 108336$

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Q:

From a deck of 52 cards, a 5 card hand is dealt.How may distinct five card hands are there if the queen of spades and the four of diamonds must be in the hand?

A) 52C5	B) 50C3
C) 52C4	D) 50C4

Answer & Explanation Answer: B) 50C3

Explanation:

If the queen of spades and the four of diamonds must be in hand,we have 50 cards remaining out of which we are choosing 3.

So, 50 $C_{3}$

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Q:

From a deck of 52 cards, a 7 card hand is dealt.How many distinct hands are there if the hand must contain 2 spades and 3 diamonds ?

A) 7250100	B) 7690030
C) 7250000	D) 3454290

Answer & Explanation Answer: A) 7250100

Explanation:

There are 13 spades,we must include 2: 13 $C_{2}$

There are 13 diamonds,we must include 3: $13 C_{3}$

Since we can't have more than 2 spades and 3 diamonds,the remaining 2 cards must be pulled out from the 26 remaining clubs and hearts : $26 C_{2}$

Therefore, $13 C_{2} * 13 C_{3} * 26 C_{2}$ = 7250100

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