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Q:

The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be  formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture ?

A) 4 B) 5
C) 8 D) None of these
 
Answer & Explanation Answer: B) 5

Explanation:

           Wine                         Water

            8L                              32L

            1                :               4

           20 %                           80% (original ratio)

           30 %                           70% (required ratio)

 

In  ths case, the percentage of water being reduced when the mixture is being replaced with wine.

 

so the ratio of left quantity to the initial quantity is 7:8

 

Therefore , 78=1-K40

 

=> K = 5 Lit

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