4
Q:

# bc _ b _ c _ b _ ccb

 A) c b c b B) b b c b C) c b b c D) b c b c

Answer:   A) c b c b

Explanation:

Here 'bccb' repeated 3 times.

b c c b | b c c b | b c c b

Q:

What is the next number in series?

10, 9, 60, 90, 70, 66, ?

 A) 73 B) 19 C) 96 D) 22

Explanation:

ten = 3(number of letters)
nine = 4(number of letters)
sixty = 5(number of letters)
ninety = 6(number of letters)
seventy = 7(number of letters)
sixtysix = 8(number of letters)
ninetysix=96(number of letters)

Then, likwise choose the number which has 9 letters in its Spelling.

Filed Under: Series - Verbal Reasoning - Mental Ability
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3 46
Q:

What is the number that should come in the place of question mark ?

1050    420    168     67.2     ?

 A) 19.11 B) 14.25 C) 10.752 D) 26.88

Explanation:

Given series follows the rule of

1050/2.5 = 420
420/2.5 = 168
168/2.5 = 67.2
so 67.2/2.5 = 26.88

Filed Under: Series - Verbal Reasoning - Mental Ability
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3 16
Q:

Find the missing number in the given series ?

15, 51, 216, 1100, ?, 46452

 A) 5660 B) 6560 C) 6750 D) 6630

Explanation:

Let first no. be "k" and multiple be "l"...start value of y with 3
then,
[(k x y) + {l x (l-1)}]
Thus, we get

15 x 3 + 3 x 2 = 51
51 x 4 + 4 x 3 = 216
216 x 5 + 5 x 4 = 1100
1100 x 6 + 6 x 5 = 6630
6630 x 7 + 7 x 6 = 46452

Therefore, the missing number is 6630.

Filed Under: Series - Verbal Reasoning - Mental Ability
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4 31
Q:

What is the next number of the following sequence ?

21, 77, 165, 285, ......

 A) 404 B) 415 C) 426 D) 437

Explanation:

The series follow the rule,

21 = $\inline \fn_jvn \small 5^{2}-4$
77 = $\inline \fn_jvn \small 9^{2}-4$
165 = $\inline \fn_jvn \small 13^{2}-4$
285 = $\inline \fn_jvn \small 17^{2}-4$

5,9,13,17,21,(+4)...
In the same way next no. will be
$\inline \fn_jvn \small 21^{2}-4$ = 441 - 4 = 437

Filed Under: Series - Verbal Reasoning - Mental Ability
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4 43
Q:

Which fraction comes next in the sequence

$\inline \fn_jvn \frac{2}{3},\frac{1}{3},\frac{5}{27},\frac{7}{81},?$

 A) 1/27 B) 11/278 C) 9/48 D) 7/123

Clearly, the numerators of the fractions in the given sequence follow the series of 2, 3, 5, 7,... and the denominator follows $\inline \fn_jvn \small 3,3^{2},3^{3},3^{4},...$
Then, the next term in the given sequence is  $\inline \fn_jvn \small \frac{9}{3^{5}} = \frac{9}{243}$ = 1/27