Quantitative Aptitude - Arithmetic Ability Questions

Q:

Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?

A) 30 km/h B) 15 km/h
C) 25 km/h D) 20 km/h
 
Answer & Explanation Answer: D) 20 km/h

Explanation:

If the speed of the faster horse be fs and that of slower horse be ss then

 fs+ss=501=50 

and       50ss-50fs=56

Now, you can go through options.

The speed of slower  horse is 20km/h

Since,   20+30=50

and  5020-5030=56    

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Filed Under: Time and Distance

159 39872
Q:

Find the volume (in cm3) of a right circular cone of diameter 7 cm and height 7 cm.

 

A) 69.06   B) 16.43  
C) 11.15   D) 89.83
 
Answer & Explanation Answer: D) 89.83

Explanation:
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 39532
Q:

The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is

A) 77 B) 88
C) 99 D) 110
 
Answer & Explanation Answer: A) 77

Explanation:

Product of numbers = 11 x 385 = 4235

 

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235  =>  ab = 35

 

Now, co-primes with product  35 are (1,35) and (5,7)

 

So, the numbers are ( 11 x 1, 11 x 35)  and (11 x 5, 11 x 7)

 

Since one number lies 75 and 125, the suitable pair is  (55,77)

 

Hence , required number = 77

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Filed Under: HCF and LCM

72 39483
Q:

I forgot the last digit of a 7-digit telephone number. If 1 randomly dial the final 3 digits after correctly dialing the first four, then what is the chance of dialing the correct number?

A) 1/999 B) 1/1001
C) 1/1000 D) 4/1000
 
Answer & Explanation Answer: C) 1/1000

Explanation:

It is given that last three digits are randomly dialled. then each of the digit can be selected out of 10 digits in 10 ways.
Hence required probability =1103 = 1/1000

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Filed Under: Probability

28 39468
Q:

The ratio 5 : 4 expressed as a percent equals :

A) 12.5 % B) 40 %
C) 80 % D) 125 %
 
Answer & Explanation Answer: D) 125 %

Explanation:

5 : 4 = 5/4 = ( (5/4) x 100 )% = 125%.

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Filed Under: Percentage

154 39338
Q:

270 candidates appeared for an examination, of which 252 passed. The pass percentage is :

A) (91 + 1/3)% B) (93 + 1/3 )%
C) (97 + 1/3 )% D) (98 + 1/3) %
 
Answer & Explanation Answer: B) (93 + 1/3 )%

Explanation:

Pass percentage  =[(252/270)*100] % =280/3 % =9313 9 %

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Filed Under: Percentage

109 39283
Q:

Tarun got 30% concession on the labelled price of an article and sold it for Rs. 8750 with 25% profit on the price he bought. What was the labelled price ?

A) 10000 B) 12000
C) 13000 D) 14000
 
Answer & Explanation Answer: A) 10000

Explanation:

Cost Price = Rs.100125×8750 = Rs. 7000. Let the labelled price be Rs. x. 

 

Then, 70100*x=7000 x=Rs.7000*10070 

 

= Rs.10000

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Filed Under: Profit and Loss

201 39274
Q:

A and B start a business jointly. A invests Rs. 16,000 for 8 months and B remains in  the business for 4 months, Out of total profit, B claims - of the profit. How much money was contributed by B ?

A) 12000 B) 12800
C) 13000 D) 14500
 
Answer & Explanation Answer: B) 12800

Explanation:

Let the total profit be Rs. x. Then, B = 2x/7 and A = (x - 2x /7) =  5x / 7.

So, A : B = 5x/7 : 2x/7 = 5 : 2.

Let B s capital be Rs. y. Then, (16000 * 8) / ( y * 4) = 5/2  <=> (16000 * 8 * 2) / (5 * 4) = 12800..  

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Filed Under: Partnership

35 39150