6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

(x-2) men can do a piece of work in x days and (x+7) men can do 75% of the same work in (x-10)days. Then in how many days can (x+10) men finish the work?

A) 27 days	B) 12 days
C) 25 days	D) 18 days

Answer & Explanation Answer: B) 12 days

Explanation:

$\frac{3}{4} \times (x - 2) x = (x + 7) (x - 10)$

$\Rightarrow x^{2} - 6 x - 280 = 0$

=> x= 20 and x=-14

so, the acceptable values is x=20

Therefore, Total work =(x-2)x = 18 x 20 =360 unit

Now 360 = 30 x k

=> k=12 days

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Filed Under: Time and Work

77 34219

Q:

Select the odd character out of the following series.

A) A	B) ¥
C) €	D) $

Answer & Explanation Answer: A) A

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 34146

Q:

The ratio of petrol and kerosene in the container is 3:2 when 10 liters of the mixture is taken out and is replaced by the kerosene, the ratio become 2:3. Then total quantity of the mixture in the container is:

A) 25	B) 30
C) 45	D) cannot be determined

Answer & Explanation Answer: B) 30

Explanation:

pool : kerosene

3 : 2(initially)

2 : 3(after replacement)

$\frac{R e m a i n i n g Q u a n t i t y}{I n i t i a l Q u a n t i t y} = (1 - \frac{R e p l a c e d Q u a n t i t y}{T o t a l Q u a n t i t y})$

(for petrol) $\frac{2}{3} = (1 - \frac{10}{k})$

=> K = 30

Therefore the total quantity of the mixture in the container is 30 liters.

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Filed Under: Alligation or Mixture

83 34145

Q:

The calendar of the year 1897 can be used again in the year?

A) 1908	B) 1901
C) 1903	D) 1926

Answer & Explanation Answer: C) 1903

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2: Add +6 to the Given Year.

Solution :

Given Year is 1897, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 1897 + 11) = 1908, Which is a leap year.

Step 2 : Add +6 to the given year (i.e 1897 + 6) = 1903

Therfore, The calendar of the year 1897 can be used again in the year 1903

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Filed Under: Calendar

88 34099

Q:

The simple interest at y% for 'y' years will be Rs. y on a sum. Find the principal amount.

A) 100/y	B) 100 x y
C) 100y2	D) 100 ÷ y2

Answer & Explanation Answer: A) 100/y

Explanation:

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Filed Under: Simple Interest
Exam Prep: Bank Exams

2 34082

Q:

Find the odd word/letters/number pair from the given alternatives.

(A) KP

(B) MN

(C) HR

(D) GT

A) A	B) B
C) C	D) D

Answer & Explanation Answer: C) C

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

1 34050

Q:

Two partners investede Rs. 1250 and Rs. 850 respectively in a business. They distributed 60% of the profit equally and decide to distribute the remaining 40% as the ratio of their capitals. If one partner received Rs. 30 more than the other, find the total profit?

Answer

Let the total profit be Rs.x

60% of the profit = $\inline \frac{60}{100}\times x=Rs.\frac{3x}{5}$

from this part of the profit each gets = Rs. $\inline \frac{3x}{10}$

40% of the profit = $\inline \frac{40}{100}\times x=Rs.\frac{2x}{5}$

Now, this amount of Rs. $\inline \frac{2x}{5}$ has been divided in the ratio of capitals 1250 : 850 = 25 :17

$\inline \therefore$ Share on first capital = $\inline (\frac{2x}{5}\times \frac{25}{42})=Rs.\frac{5x}{21}$

Share on second capital = $\inline (\frac{2x}{5}\times \frac{17}{42})=Rs.\frac{17x}{105}$

Total money received by 1st investor = $\inline [\frac{3x}{10}+\frac{5x}{21}]= Rs.\frac{113x}{210}$

Total money received by 2nd investor = $\inline [\frac{113x}{210}+\frac{97x}{210}]=Rs.\frac{97x}{210}$

$\inline \therefore$ x = 393.75

Hence total profit = Rs. 393.75

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Subject: Partnership

105 33969

Q:

Find the odd word/letters/number pair from the given alternatives.

(A) Square (B) Sphere (C) Rectangle (D) Circle

A) A	B) B
C) C	D) D

Quantitative Aptitude - Arithmetic Ability Questions

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