# Job Roles

A) immortal | B) aggravating |

C) immoral | D) fecund |

A) Quantity1 < Quantity2 | B) Quantity1 ≤ Quantity2 |

C) Quantity1 ≥ Quantity2 | D) Quantity1 > Quantity2 |

Explanation:

Quantity1-

Rakhi’s marks= 115

Meenakshi’s marks= 115 - 20 = 95

Puneeta’s marks= 95 + 65= 160

Ankita’s marks=160 - 35= 125

Simpy’s marks= 125+ 67= 192

Total maximum marks= 192 + 108= 300

Required percentage marks of Simpy

= $\frac{192}{300}\times 100=64\%$

Quantity2-

Let length and breadth be 100.

After increase in length it become 160, then

reduction in breadth be ‘x’

Now, 160*x= 100*100

Hence, x = $\frac{10000}{160}=62.5$

100-62.5=37.5%

A) Quantity 1 > Quantity 2 | B) Quantity 1 ≥ Quantity 2 |

C) Quantity 1 < Quantity 2 | D) Quantity 1 ≤ Quantity 2 |

Explanation:

Quantity 1:

Let the first pipe alone takes x hours to fill the

tank.

⇒The second and third pipes will take (x-5) and

(x-9) hours respectively.

According to the given information:

∴ $\frac{1}{x-9}$

⇒ (x-9)(2x-5) = x2 – 5x

⇒ 2x2 – 5x – 18x + 45 = x2 – 5x

⇒ x

2 -18x + 45 = 0

⇒ (x-15) (x-3) = 0

⇒ x = 15, 3

The first pipe can take 15 hours to fill the kund.

∵ 3 hours doesn’t satisfy the statement.

Quantity 2:

∴ Time taken by second pipe = x-5

⇒ Time taken by second pipe = 15-5 = 10hours

∴ Time taken by third pipe = x -9

⇒ Time taken by third pipe = 15- 9 = 6 hours

Now,

Net part filled in 1 hour = $\frac{1}{15}+\frac{1}{10}+\frac{1}{6}$

⇒ Net part filled in 1 hour = $\frac{4+6+10}{60}$

⇒Net part filled in 1 hour = $\frac{20}{60}=\frac{1}{3}$

∴The Kund will be full in 3/1 hours if all the pipes are opened simultaneously

Now, comparing

15 > 3

Thus, Quantity 1 > quantity 2

A) Quantity I > Quantity II | B) Quantity I < Quantity II |

C) Quantity I ≥ Quantity II | D) Quantity I ≤ Quantity II |

A) 5/7 | B) 5/14 |

C) 1/7 | D) 1/14 |

Explanation:

Required probability = $\frac{(10+3)}{91}=\frac{13}{91}=\frac{1}{7}$

A) 3/14 | B) 2/91 |

C) 9/182 | D) 7/545 |

Explanation:

Required probability = $\frac{3\times 6}{364}=\frac{9}{182}$

A) I and II | B) I and III |

C) Only III | D) I and either II or III |

Explanation:

From I and II,

Length = 3x = 48 m

∴ x = 16

Breath = 2x = 32 m

Hence, Area of floor = 48 × 32

Cost of flooring = 48 × 32 × 850 = ₹ 1305600

From I and III, 2(l +b) = 160

2(3x + 2x) = 160

10x = 160

∴ x = 16

∴ Length = 3 × 16 = 48 m

Breadth = 2x = 32m

Cost of flooring = (48 × 32) × 850 = ₹ 1305600

Similarly, from II and III, we can find

l = 48 m

b = 32 m

and Total cost of flooring = ₹ 1305600